Question

在进行sql查询时，我有一个字段 Gift_Number ，它给我以下数据

Gift certificat (-) [2989153053216]
Sql Query：

           SELECT SUBSTRING(H.F1056, patindex('%[^0]%',H.F1056), 10) AS Shop_Number
                  , '000' AS Cashier_Code
                  , H.F1057 AS Terminal_number
                  , REPLACE(CONVERT(VARCHAR(10), H.F254, 103), '/', '') AS Todays_Date
                  , STIME AS Ticket_Time
                  , H.F1032 AS Ticket_Number
                  , K.F1063 AS Mode_Of_Payment
                  , K.F02 AS Mode_Of_Payment_Desc
                  , CASE WHEN J.F1063 = 117 
                         THEN J.F02 
                         ELSE '' END AS Gift_Number
                  , CASE WHEN I.F02 = 'TOTAL' 
                         THEN I.F65 
                         ELSE 0 END AS Total_Ticket
             FROM [READEJ_H] H
  LEFT OUTER JOIN [dbo].[READEJ_I] I 
               ON (H.F1101 = I.F1101 AND I.F02 = 'TOTAL')
  LEFT OUTER JOIN [dbo].[READEJ_I] K 
               ON (H.F1101=K.F1101 AND K.F1063 BETWEEN 100 AND 199)
  LEFT OUTER JOIN [dbo].[READEJ_I] J 
               ON (H.F1101=J.F1101 AND J.F1063 = 117)
            WHERE I.F65  <> CONVERT(DOUBLE PRECISION,0)

如何仅提取sql select语句中方括号之间的信息。输出应如下所示：

    2989153053216

Answer 1

可能最简单的方法是使用charindex和substring：

DECLARE @S varchar(100) = 'Gift certificat (-) [2989153053216]'

SELECT SUBSTRING(@S, CHARINDEX('[', @S)+1, CHARINDEX(']', @S) - CHARINDEX('[', @S)-1)

结果：2989153053216

但是，您应该知道，如果字符串不包含分隔符，或者]分隔符位于[分隔符之前，则会引发错误。

从SQL中的方括号中提取数据

1 个答案: