Question

我在（C：/Users/kgu/PycharmProjects/untitled1/test1.py）中保存了csv文件。命名为testdata.csv

我的代码是：

import csv
f=open('testdata.csv','r',encoding='utf-8')

错误信息在这里：

C:\Users\kgu\Anaconda3\python.exe 
C:/Users/kgu/PycharmProjects/untitled1/test1.py
Traceback (most recent call last):
File "C:/Users/kgu/PycharmProjects/untitled1/test1.py", line 3, in <module>
f=open('testdata.csv','r',encoding='utf-8')
FileNotFoundError: [Errno 2] No such file or directory: 'testdata.csv'

Process finished with exit code 1

我确实将testdata.csv保存在python项目文件夹中。我不知道它有什么问题。

Answer 1

如果您使用Pandas，可以尝试：

import pandas as pd

filepath = "/yourfilepath/yourfile.csv"
# check your sep (";" , "," ...)
f = pd.read_csv(filepath, encoding="utf-8", sep="yoursep")

Answer 2

你可以这样做 - 如果你在正确的工作目录中：

with open(testdata.csv', 'rb') as csvfile:
    data = [x for x in csv.reader(csvfile, delimiter='yourdelimiter')]

在Python中打开csv文件时出错

2 个答案: