如何确定ToolStripMenuItem的父级?使用普通的MenuStrip,您只需使用Parent属性,但ToolStripMenuItem似乎没有该属性。我有一个ToolStripDropDownButton,它有几个ToolStripMenuItems,我希望能够以编程方式精确定位那些父类。
答案 0 :(得分:19)
尝试OwnerItem属性。
答案 1 :(得分:5)
这对我有用:
ToolStripMenuItem menuItem = sender as ToolStripMenuItem;
ToolStrip toolStrip = menuItem.GetCurrentParent();
...从这里开始,您可以设计一种方法,将您从随机ToolStripMenuItem带到最高级别:
public static class ToolStripItemExtension
{
public static ContextMenuStrip GetContextMenuStrip(this ToolStripItem item)
{
ToolStripItem itemCheck = item;
while (!(itemCheck.GetCurrentParent() is ContextMenuStrip) && itemCheck.GetCurrentParent() is ToolStripDropDown)
{
itemCheck = (itemCheck.GetCurrentParent() as ToolStripDropDown).OwnerItem;
}
return itemCheck.GetCurrentParent() as ContextMenuStrip;
}
}
答案 2 :(得分:3)
试试这个......
ToolStripMenuItem t = (ToolStripMenuItem)sender;
ContextMenuStrip s = (ContextMenuStrip)t.Owner;
MessageBox.Show(s.SourceControl.Name);
答案 3 :(得分:0)
这就是你要找的东西
private void ContextMenuStrip_Opening(object sender, CancelEventArgs e)
{
contextMenuStrip1.Tag = ((ContextMenuStrip)sender).OwnerItem;
}
private void ToolStripMenuItem_Click(object sender, EventArgs e)
{
ToolStripMenuItem senderItem = (ToolStripMenuItem)sender;
var ownerItem = (ToolStripMenuItem)((ContextMenuStrip)senderItem.Owner).Tag;
}
答案 4 :(得分:0)
在搜索了许多关于该问题的帖子后,我发现这对我有用:
ToolStripMenuItem mi = (ToolStripMenuItem)sender;
ToolStripMenuItem miOwnerItem = (ToolStripMenuItem)(mi.GetCurrentParent() as ToolStripDropDown).OwnerItem;