Question

我使用SELECT语句在表中选择了一个特定的ROW。在这一行中，我想找到包含特定字符串的列。

import websocket
import thread
import time
import json

def on_message(ws, message):
    print(message)

def on_error(ws, error):
    print(error)

def on_close(ws):
    print("### closed ###")

def on_open(ws):
    print("ONOPEN")
    def run(*args):
        ws.send(json.dumps({'command':'subscribe','channel':1001}))
        ws.send(json.dumps({'command':'subscribe','channel':1002}))
        ws.send(json.dumps({'command':'subscribe','channel':1003}))
        ws.send(json.dumps({'command':'subscribe','channel':'BTC_XMR'}))
        while True:
            time.sleep(1)
        ws.close()
        print("thread terminating...")
    thread.start_new_thread(run, ())


if __name__ == "__main__":
    websocket.enableTrace(True)
    ws = websocket.WebSocketApp("wss://api2.poloniex.com/",
                              on_message = on_message,
                              on_error = on_error,
                              on_close = on_close)
    ws.on_open = on_open
    ws.run_forever()

我想知道哪个列包含字符串E.谢谢。

Answer 1

您可以执行以下操作：

select (case when col1 = 'E' then 'col1'
             when col2 = 'E' then 'col2'
             when col3 = 'E' then 'col3'
             when col4 = 'E' then 'col4'
             when col5 = 'E' then 'col5'
        end)

如果您只想要索引：

select field('E', col1, col2, col3, col4, col5)

如何获取包含mysql行中的字符串的列名

1 个答案: