标签: scala unfiltered
鉴于unfiltered HttpRequest,如何修改uri?
unfiltered
uri
示例:
val req:unfiltered.request.HttpRequest [javax.servlet.http.HttpServletRequest] = ???
如何更新unfiltered.request.HttpRequest[javax.servlet.http.HttpServletRequest]来生成新的uri?
unfiltered.request.HttpRequest[javax.servlet.http.HttpServletRequest]