这是DATASET:
这是我的SQL:
select f.DATE, f.PROD_STATUS,
count (*) AS TOTAL
from PROD_TABLE f
where DATE = '04-MAY-17'
GROUP BY f.DATE, f.PROD_STATUS
我正在尝试将'SUCCESS'
的值作为SQL结果中的列:
(SUCCESS = READY_1 + READY_2 + READY_3 + READY_4 + READY_5)
我希望SQL结果如下所示:
我怎样才能做到这一点?
答案 0 :(得分:0)
检查一下:
with t as (
select 1 as ready_1,
2 as ready_2,
3 as ready_3,
1 as in_process,
4 as fail,
5 as crash,
'5/4/2017' as dat
from dual
union all
select 2 as ready_1,
2 as ready_2,
3 as ready_3,
1 as in_process,
4 as fail,
0 as crash,
'5/5/2017' as dat
from dual
)
select dat, prod_stat, max(suc) over(partition by dat) as success, sum(value) over(partition by dat) as total
from (
select dat, prod_stat, value, sum(value) over (partition by dat) as suc
from t
unpivot(
value for prod_stat in (ready_1, ready_2, ready_3)
)
union all
select dat, prod_stat, value, null as suc
from t
unpivot(
value for prod_stat in (in_process, fail, crash)
)
)
结果:
DAT PROD_STAT SUCCESS TOTAL
5/4/2017 READY_2 6 16
5/4/2017 READY_1 6 16
5/4/2017 CRASH 6 16
5/4/2017 FAIL 6 16
5/4/2017 IN_PROCESS 6 16
5/4/2017 READY_3 6 16
5/5/2017 FAIL 7 12
5/5/2017 IN_PROCESS 7 12
5/5/2017 CRASH 7 12
5/5/2017 READY_2 7 12
5/5/2017 READY_1 7 12
5/5/2017 READY_3 7 12