Question

我无法弄清楚如何区分不同的位掩码。

我希望这种情况发生：

 /*func didBegin(_ contact: SKPhysicsContact) {
if (spaceship1 collides with spaceship2) {
    print("contact between 1 and 2")
    }
if (spaceship1 collides with spaceship3) {
print("contact between 1 and 3")
    }
}
*/

这是我尝试过的代码：

    func didBegin(_ contact: SKPhysicsContact) {
    if (contact.bodyA.categoryBitMask = enemyCategory && contact.bodyB.categoryBitMask = enemy2Category) {
        print("contact between 1 and 2")
    }
}

我能得到一些帮助吗？

编辑：这是其他代码：

import SpriteKit
import GameplayKit

class GameScene: SKScene, SKPhysicsContactDelegate {

let enemy2Category: UInt32 = 1

let enemyCategory: UInt32 = 2

let enemy3Category: UInt32 = 3

var spaceship1: SKSpriteNode!
var spaceship2: SKSpriteNode!
var spaceship3: SKSpriteNode!

override func didMove(to view: SKView) {
    self.physicsWorld.contactDelegate = self
    spaceship1 = SKSpriteNode(imageNamed: "Spaceship");
    spaceship1.setScale(CGFloat(0.1))
    spaceship1.position = CGPoint(x: self.frame.width / 2, y: (self.frame.height / 2));
    spaceship1.name = "spaceship1";


    spaceship1.physicsBody = SKPhysicsBody(circleOfRadius: spaceship1.size.width / 2);
    spaceship1.physicsBody?.isDynamic = true // apply gravity, friction, and collision
    spaceship1.physicsBody?.affectedByGravity = true;
    spaceship1.physicsBody?.allowsRotation = false
    spaceship1.physicsBody = SKPhysicsBody(circleOfRadius: spaceship1.size.width / 2);
    spaceship1.physicsBody?.categoryBitMask = enemy2Category
    spaceship1.physicsBody?.collisionBitMask = enemyCategory
    spaceship1.physicsBody?.contactTestBitMask = enemyCategory

    spaceship2 = SKSpriteNode(imageNamed: "Spaceship");
    spaceship2.setScale(CGFloat(0.1))
    spaceship2.position = CGPoint(x: self.frame.width / 2, y: (spaceship1.position.y + 300));
    spaceship2.name = "spaceship2";

    spaceship2.physicsBody = SKPhysicsBody(circleOfRadius: spaceship2.size.width / 2);
    spaceship2.physicsBody?.isDynamic = true // apply gravity, friction, and collision
    spaceship2.physicsBody?.affectedByGravity = false;
    spaceship2.physicsBody?.allowsRotation = false
    spaceship2.physicsBody = SKPhysicsBody(circleOfRadius: spaceship2.size.width / 2);
    spaceship2.physicsBody?.categoryBitMask = enemyCategory
    spaceship2.physicsBody?.collisionBitMask = enemy2Category
    spaceship2.physicsBody?.contactTestBitMask = enemy2Category

    spaceship3 = SKSpriteNode(imageNamed: "Spaceship");
    spaceship3.setScale(CGFloat(0.1))
    spaceship3.position = CGPoint(x: self.frame.width / 2, y: (spaceship1.position.y + 300));
    spaceship3.name = "spaceship3";

    spaceship3.physicsBody = SKPhysicsBody(circleOfRadius: spaceship2.size.width / 2);
    spaceship3.physicsBody?.isDynamic = true // apply gravity, friction, and collision
    spaceship3.physicsBody?.affectedByGravity = false;
    spaceship3.physicsBody?.allowsRotation = false
    spaceship3.physicsBody = SKPhysicsBody(circleOfRadius: spaceship2.size.width / 2);
    spaceship3.physicsBody?.categoryBitMask = enemy3Category
    spaceship3.physicsBody?.collisionBitMask = enemy2Category | enemyCategory
    spaceship3.physicsBody?.contactTestBitMask = enemy2Category | enemyCategory


    addChild(spaceship1)

}


        override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    addChild(spaceship3)
}

    override func update(_ currentTime: TimeInterval) {
        spaceship1.physicsBody?.affectedByGravity = false;
}

}

我只想弄清楚如何检测哪些位掩码相互接触。就像宇宙飞船1与太空船2接触一样，它会打印出来，但是如果宇宙飞船1与宇宙飞船3接触，它会打印出来＃34;哇哇哇哇哇哇

Answer 1

你在if语句中缺少一个=。

func didBegin(_ contact: SKPhysicsContact) {
    if (contact.bodyA.categoryBitMask == enemyCategory && contact.bodyB.categoryBitMask == enemy2Category) {
        print("contact between 1 and 2")
    }
}

Answer 2

有一篇文档文章试图解释Sprite-Kit冲突和联系人中使用的位掩码，但我无法再链接到它。试着找到＆＃39;文档＆＃39;页面，标签＆＃39; Sprite-Kit＆＃39;然后操纵contactTest和collison位掩码来启用/禁用特定的接触和碰撞。＆＃39; ＆＃39; SKNode Collision＆＃39;。

下的文章

这一行有一个明显的问题：

let enemy3Category: UInt32 = 3

所有位掩码都有被认为是二进制的，而二进制3中则是11.这是＆＃39; 1＆＃39;位和＆＃39; 2＆＃39;将两者都设置为1. 类别定义应该只有1位设置为1，您可以通过对类别使用2的精确幂来确保 - 1,2,4,8,16,32等

场景中需要碰撞/联系的对象最初应该只属于一个类别。对于更高级的联系人和冲突，精灵可以属于多个类别。

Answer 3

这将firstBody设置为较小的位掩码并将secondBody设置为较大的位掩码

        var firstBody = SKPhysicsBody()
        var secondBody = SKPhysicsBody()

        if contact.bodyA.categoryBitMask < contact.bodyB.categoryBitMask {
            firstBody = contact.bodyA
            secondBody = contact.bodyB
        }else{
            firstBody = contact.bodyB
            secondBody = contact.bodyA
        }

确认bitmask1小于2和3。

        if firstBody.categoryBitMask == bitMask1 && secondBody.categoryBitMask == bitMask.bitmask3 {
            print("a")

        //If ball hits a pad, activate the pad
        }else if firstBody.categoryBitMask == bitMask1 && secondBody.categoryBitMask == bitMask.bitmask2 {
            print("e")
}

区分不同的位掩码

3 个答案: