我有一个名为$lines
的字符串数组,我想用每个字符串搜索数据库。
我的工作原理是什么:
foreach($lines as $line) {
$line = real_escape_string($line);
$sql = "select * from $table where $column like '%$line%'"
$result = $conn->query($sql);
if($result->num_rows) {
while ($row = $result->fetch_assoc())
//Name and Date are are only 2 out of 15+ column names from the db table
echo "<tr><td> {$row['Name']} </td>
<td> {$row['Date']} </td></tr>";
}
但是,我不想要这个。我想使用预准备语句,并能够使用上面的列名。我尝试过的:(来自here)
$vars = array();
$data = array();
$stmt = $conn->prepare("SELECT * FROM $table WHERE `$column` LIKE '%?%'");
$stmt->bind_param("s", $line);
$stmt->execute();
$result = $stmt->store_result();
$meta = $result->result_metadata();
echo "WORKS"; //doesn't print
while ($field = $meta->fetch_field())
$vars[] = &$data[$field->name];
call_user_func_array(array($result, 'bind_result'), $vars);
$i = 0;
while ($result->fetch()) {
$array[$i] = array();
foreach ($data as $k=>$v)
$array[$i][$k] = $v;
$i++;
}
print_r($array);
答案 0 :(得分:1)
由于使用预准备语句绕过了对引号的需要并传递了确切变量,因此需要在变量中传递通配符,而不是在查询中:
$stmt = $conn->prepare("SELECT * FROM $table WHERE `$column` LIKE ?");
$stmt->bind_param("s", '%'.$line.'%');