Question

如何修复程序中的<zip object at 0x03B1C3C8>

class Student(object):
    def __init__(self, name, surname, grade, hours):
        self.name = name
        self.surname = surname
        self.grade = grade
        self.hours = hours

    def getName(self):
        return '{}'.format(self.name)

    def getSurname(self):
        return '{}'.format(self.surname)

    def getGrade(self):
        return zip(self.grade, self.hours)

    def getHours(self):
        return '{}'.format(self.hours)

    def getQPoints(self):
        pass

stud1 = Student("John","Brown",["A","B","A"],["15.0","25.0","20.0"])
stud2 = Student("Mary","Watson","B","20")

print (stud1.getGrade())
print (stud1.getHours())

Answer 1

只需使用list()，如下所示：

def getGrade(self):
    return list(zip(self.grade, self.hours))

注意：如果您只需要循环返回的list()对象，则无需应用zip。

>>> for i, j in stud1.getGrade():
...     print(i, j)
...
('A', '15.0')
('B', '25.0')
('A', '20.0')

Answer 2

我说你完全忘了拉链：

class Student(object):
    def __init__(self, name, surname, grade, hours):
        self.name = name
        self.surname = surname
        self.grade = grade
        self.hours = hours

    def getName(self):
        return '{}'.format(self.name)

    def getSurname(self):
        return '{}'.format(self.surname)

    def getGrade(self):
        return (self.grade, self.hours)

    def getHours(self):
        return '{}'.format(self.hours)

    def getQPoints(self):
        pass

stud1 = Student("John","Brown",["A","B","A"],["15.0","25.0","20.0"])
stud2 = Student("Mary","Watson","B","20")

print (stud1.getGrade())
print (stud1.getHours())

return (self.grade, self.hours)将创建一个可以打印的元组

Answer 3

从python文档中，当你使用zip时，它返回一个元组的迭代器（python使用这些＆＃39; ()＆＃39;来定义。）

如此迭代你的成绩元组可能是最简单的：

for grade in stud1.getGrades():
    print("Grade: " + grade[0] + " Hours studied: " + grade[1])

这会给你：

Grade: A Hours studied: 15.0
Grade: B Hours studied: 25.0
Grade: A Hours studied: 20.0

但我宁愿让Student.getGrade仅返回成绩列表。然后有另一个函数getReport来打印小时数和成绩。

如何在数组中打印出对值

3 个答案: