嘿伙计们,我有一个网站,其网址看起来像这样: www.domain.com/photos.php?id=(image id); 现在,我的问题是,如何使用mysql和php为每张图片添加注释。
答案 0 :(得分:3)
您可能需要一个新表来将用户链接到带有图片的评论:
表:评论
id (comment id), user (user id), picture (pic id), comment (text), date(timestamp w/default current time)
然后在显示图像后,对任何注释执行另一个查询:
$comments_query = mysql_query("SELECT comment FROM comments WHERE picture = $id");
while($comments_result = mysql_fetch_array($comments_query)){
echo($comments_result['comment']);
}
您也可能希望将每个用户的用户名链接到评论:
$comments_query = mysql_query("SELECT comments.comment, users.username, comments.date FROM comments INNER JOIN users ON comments.user = users.id WHERE comments.picture = $id");
while($comments_result = mysql_fetch_array($comments_query)){
echo($comments_result['date']);
echo($comments_result['username']);
echo($comments_result['comment']);
}