Question

我从另一个表中获得了结果集。父表上的QUERY：

SELECT Type, COUNT(Result) AS [Counts]
FROM ParentTable
GROUP BY Type

结果：

=============== 
TYPE  |  Counts 
=============== 
Type1  | 43 
Type2  | 13 
Type3  | 16

我需要输出格式如下......

===============================   
TYPE   | COUNTs  | [Percentage]     
===============================    
Type1  | 43        |   59.72 
Type2  | 13        |   18.06 
Type3  | 16        |   22.22

Answer 1

大多数数据库都支持ANSI标准窗口函数。你可以这样做：

SELECT Type, COUNT(Result) AS [Counts],
       COUNT(Result) * 1.0 / SUM(COUNT(Result)) OVER () as ratio
FROM ParentTable
GROUP BY Type ;

Answer 2

你可以试试;我只将COUNT更改为SUM以简化答案。

  declare @ParentTable as table (Type char(5) , Result int)  
    INSERT @ParentTable (Type, Result) values 
    ('Type1' , 43 ),
    ('Type2' , 13 ),
    ('Type3' , 16 )




     SELECT Type, 
SUM(Result) OVER ( PARTITION BY Type)  AS [Counts] , 
Round(Cast(SUM(Result) OVER ( PARTITION BY Type) as float)  /  Cast(SUM(Result) OVER (PARTITION BY 1) as float) * 100. ,2) Percentage
        FROM @ParentTable


Type  Counts      Percentage
----- ----------- ----------------------
Type1 43          59.72
Type2 13          18.06
Type3 16          22.22

sql表中列的平均值

2 个答案: