Question

我正在制作一个程序并希望用户选择他们的兴趣，并在完成后按提交。如果选中至少一个按钮，我怎么才允许用户按提交。

from tkinter import *

check = Tk()
check.title("Interests")
CheckVar1 = IntVar()
CheckVar2 = IntVar()
CheckVar3 = IntVar()
CheckVar4 = IntVar()
CheckVar5 = IntVar()


C1 = Checkbutton(check, text = "Horror", variable = CheckVar1, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C2 = Checkbutton(check, text = "Action", variable = CheckVar2, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C3 = Checkbutton(check, text = "Documentary", variable = CheckVar3, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C4 = Checkbutton(check, text = "Science fiction", variable = CheckVar4, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C5 = Checkbutton(check, text = "Comedy", variable = CheckVar5, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)

submit_btn = Button(check, text = "Submit", command = lambda: check.destroy())     


C1.pack()
C2.pack()
C3.pack()
C4.pack()
C5.pack()
submit_btn.pack()
check.mainloop()

if CheckVar1.get():
    #dosomething
if CheckVar2.get():
    #dosomething
if CheckVar3.get():
    #dosomething
if CheckVar4.get():
    #dosomething
if CheckVar5.get():
    #dosomething

Answer 1

在销毁窗口之前，您需要添加一个处理函数来检查是否至少检查了一个框。

您可以使用以下逻辑轻松完成此操作：

from tkinter import *
from tkinter import messagebox

check = Tk()
check.title("Interests")

CheckVar1 = BooleanVar()
CheckVar2 = BooleanVar()
CheckVar3 = BooleanVar()
CheckVar4 = BooleanVar()
CheckVar5 = BooleanVar()


C1 = Checkbutton(check, text = "Horror", variable = CheckVar1, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C2 = Checkbutton(check, text = "Action", variable = CheckVar2, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C3 = Checkbutton(check, text = "Documentary", variable = CheckVar3, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C4 = Checkbutton(check, text = "Science fiction", variable = CheckVar4, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)
C5 = Checkbutton(check, text = "Comedy", variable = CheckVar5, \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20)


def submitHandle():
    anyChecked = CheckVar1.get() | CheckVar2.get() | CheckVar3.get(
    ) | CheckVar4.get() | CheckVar5.get()
    if anyChecked:
        check.destroy()
    else:
        messagebox.showerror("Error", "Please check at least one.")


submit_btn = Button(check, text="Submit", command=lambda: submitHandle())

C1.pack()
C2.pack()
C3.pack()
C4.pack()
C5.pack()
submit_btn.pack()
check.mainloop()

P.S。请注意，您应该使用BooleanVar而不是IntVar来启用开关复选框。另外，请在窗口关闭时考虑adding a check。

Answer 2

为了使这更容易处理，您可以创建一个兴趣列表，然后使用它们循环所有内容。这也将使将来更容易添加内容，例如：

from tkinter import *

check = Tk()
check.title("Interests")

def destroy():
    if 1 in [vars[interest].get() for interest in interests]:
        check.destroy()

interests = ["Horror", "Action", "Documentary", "Science fiction", "Comedy"]

vars = {interest:IntVar() for interest in interests}
boxes = [Checkbutton(check, text = interest, variable = vars[interest], \
                 onvalue = 1, offvalue = 0, height=1, \
                 width = 20) for interest in interests]

submit_btn = Button(check, text = "Submit", command = destroy)


tmp = [box.pack() for box in boxes]
submit_btn.pack()

如何强制用户选择至少一个复选按钮

2 个答案: