Question

我正在尝试在Laravel WHERE IN

中的原始DB查询中绑定数组

示例：

$arr = [1,2,3];
DB::select(DB::raw("select * from test1 WHERE id IN ? "), [$arr]);

由于某种原因，数组未更改为以下查询：

select * from test1 WHERE id IN (1,2,3)

有人知道我能以某种方式做到这一点吗？

Answer 1

在laravel中尝试：

$arr = [1,2,3];
$result = DB::table('test1')->whereIn('id', $arr)->get();
dd($result);

并将此一个用于原始查询：

$arr = [1,2,3];
$arr = join(",",$arr);
$result =  DB::select(DB::raw("SELECT * FROM test1 WHERE id IN (".$arr.")"));
dd($result);

为了防止sql注入你使用我在下面提到的东西。

 $arr = [1,2];
 $arr = join(",",$arr);
 $result =  DB::select(DB::raw("SELECT * FROM test1 WHERE id IN (?,?)"),$arr);
 dd($result);

它将为你工作。

Answer 2

或

class EnhancedTable extends Component {
    state = {
        selected: [],
        data,
        order: {
            direction: 'asc',
            by: 'deviceID',
        },
        search: '',
    }

    handleRequestSort = (event, property) => {
        const orderBy = property
        let order = 'desc'

        if (this.state.order.by === property && this.state.order.direction === 'desc') {
            order = 'asc'
        }

        const data = this.state.data.sort(
            (a, b) => order === 'desc' ? b[orderBy] > a[orderBy] : a[orderBy] > b[orderBy],
        )

        this.setState({ data, order })
    }

    deleteSelected = () => {
        const {data, selected} = this.state

        this.setState({data: data.filter(item => !selected.includes(item)), selected: []})
    }

    handleSearch = event => {
        const {data} = this.state
        let filteredDatas = []
        filteredDatas = data.filter(e => {
            let mathedItems = Object.values(e)
            let returnedItems
            mathedItems.forEach(e => {
                const regex = new RegExp(event.target.value, 'gi')
                if (typeof e == 'string')
                    returnedItems = e.match(regex)
            })
            return returnedItems
        })
        this.setState({filterData: filteredDatas, search: event.target.value})
    }

     unselectSelected = () => {
         this.setState({selected: []})
     }

    duplicate = (data, selected) => {
        // const {data, selected} = this.state

        this.setState({
            // data: data.filter((item, index) => selected.includes(index)).reduce((p, c) => [...p, {...data[index]}], data),
            // data : [...data, ...selected],
            data : data,
            selected: selected,
        })

    }

handleSelectChange = selected => {
    this.setState({selected})
}

    render = () => {

        const {selected, data, search, order} = this.state

        return (
            <Paper>
                <Table
                    data={data}
                    selectable
                    columns={columns}
                    order={order}
                    search={search}
                    selected={selected}
                    onSelect={this.handleSelectChange}
                    onDelete= {this.deleteSelected}
                    onSort={this.handleRequestSort}
                    onDuplicate={this.duplicate}
                    onSearch={this.handleSearch}
                />
            </Paper>)
    }
}
export default EnhancedTable

https://laravel.com/docs/5.4/queries#where-clauses

Answer 3

$arr = [1,2,3];
$placeholders = implode(",", array_fill(0, count($arr), '?'));

DB::select("select * from test1 WHERE id IN ($placeholders)", $arr);

这个例子：

支持任意长度的数组
不包含循环
安全地传递参数

在这个例子中，我用等于数组长度的问号数量填充了一个新数组。然后我粘上新数组，用逗号分隔，并得到“？，？，？，......”。然后我在括号运算符“IN”之间插入这个子字符串。我将项目数组本身作为 select 函数的第二个参数传递。因此，元素数组的每个元素在“IN”运算符中都有自己的占位符。

Answer 4

或Eloquent：

$q= TestModel::where('id',$arr)->get();

Answer 5

尝试：

const updateDate = () => {
    let date = new Date();
    let month = date.getMonth() + 1;
    if (month < 10) {
        month = '0' + month;
    };
    let calenDay = date.getDate();
    if (calenDay < 10) {
        calenDay = '0' + calenDay;
    }
    return ({
        date: `${date.getFullYear()}-${month}-${calenDay}`,
        time: `${date.getHours()}:${date.getMinutes()}`
    });
}

const confirmOrder = () => {
    const date = updateDate();
    axiosWithAuth()
        .post(`/diner/${props.account.id}/confirm-order`, { ...date, ...orderData })
        .then(res => {
            console.log(res);
        })
        .catch(err => console.log(err));
}

在DB :: raw laravel 5.4中的数组绑定中的WHERE

5 个答案: