使用forEachFeatureatPixel函数时,Firefox和IE在OPENLAYERS 3中运行速度非常慢。我正试图找到一种加快速度的方法。从本质上讲,应用程序(在www.penguinmap.com上找到)具有弹出窗口,当用户将鼠标悬停在地图上的某个点上时。但是Firefox正在努力解决这个问题。我正在寻找以下代码的帮助来加快速度:
var selectMouseMove = new ol.interaction.Select({
condition: function (e) {
return e.originalEvent.type == 'mousemove';
},
style: hoverStyle
})
// Change cursor
var target = map.getTarget();
var jTarget = typeof target === "string" ? $("#" + target) : $(target);
// On Hover, change the mouse cursor and display the name of the site
$(map.getViewport()).on('mousemove', function (e) {
var pixel = map.getEventPixel(e.originalEvent);
var feature = map.forEachFeatureAtPixel(pixel,
function (feature, layer) {
return feature;
});
if (feature) {
map.addInteraction(selectMouseMove)
jTarget.css("cursor", "pointer");
var geometry = feature.getGeometry();
var coord = geometry.getCoordinates();
popup.setPosition(coord);
$(element).popover({
'placement': 'top',
'html': true,
'content': feature.get('site_name')
});
$(element).popover('show');
} else {
map.removeInteraction(selectMouseMove)
jTarget.css("cursor", "");
$(element).popover('destroy');
}
});
var element = document.getElementById('popup');
var popup = new ol.Overlay({
element: element,
positioning: 'bottom-center',
stopEvent: false
});
map.addOverlay(popup);
答案 0 :(得分:0)
我解决了这个问题只有点(我在IE 11上也有慢性能问题)有自己的功能。
// Alternative FeatureAtPixel-Function wegen FF
// Sucht im Rechteck vom Punkt pixel aus in +/- x und +/- y
function FFIE_getFeatureAtPixelQuadrat(pixel, DiffCoord) {
result = [];
mousepixel = map.getCoordinateFromPixel(pixel);
f = vectorSource.getFeatures();
c = 0;
for (var i in f) {
if (f[i].point.flatCoordinates[0] > mousepixel[0] - DiffCoord && f[i].point.flatCoordinates[0] < mousepixel[0] + DiffCoord ) {
if (f[i].point.flatCoordinates[1] > mousepixel[1] - DiffCoord && f[i].point.flatCoordinates[1] < mousepixel[1] + DiffCoord ) {
c++;
result.push(f[i]);
}}
}
if (c > 0) {
return result;
}
}
我参加的DiffCoord参数&#34; moveend&#34;事件:
// Event, wenn Zoom neu gesetzt
map.on("moveend", function(evt) {
// Berechnen flatCoordinates per Pixel
var pixel = [0,0];
startx = map.getCoordinateFromPixel(pixel)[0];
pixel = [1,1];
endx = map.getCoordinateFromPixel(pixel)[0];
DiffCoord = (endx-startx) * 8; // 8 entspricht den +/- Pixeln in flatCoordinates
});
现在,对于mousemove上的弹出窗口,IE和FF似乎与Chrome相同。 此示例仅适用于点,因为它在点的原点周围的正方形中搜索要素。 我希望这有帮助吗?