下面是codeigniter单列$this->db->where_in('x1',$val);
子句where_in
如何在CodeIgniter select * from tab1 where (col1,col2) in ((1,2),(2,3))
子句中传递多个列,如下面的MySQL查询nodeData.items = [];
$scope.newSubItem = function(scope) {
var nodeData = scope.$modelValue;
if(nodeData && nodeData.items ){
}
};
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答案 0 :(得分:0)
假设您的数据数组是这样的(应该是)
$val1 = array(1,2);
$val2 = array(2,3);
查询应该是
$this->db->select('*');
$this->db->from('tab1');
$this->db->where_in('col1',$val1);
$this->db->or_where_in('col2',$val2);
$query = $this->db->get();
$result = $query->result_array();
否则你可以使用
$this->db->query("select * from tab1 where (col1,col2) in ($val1,$val2)");
答案 1 :(得分:0)
" $ arr_1 = some_array;"
" $ arr_2 =某个数组;"
如果它们是同一个数组,只需将$array_2
替换为$arr_1
$result = $this->db->select('*')->where_in('col1',$arr_1)->where_in('col2',$arr_2)->get('tab1')->result_array();
OR
$result = $this->db->select('*')->where_in('col1',$arr_1)->or_where_in('col2',$arr_2)->get('tab1')->result_array();