将列数据计算为一行

Question

在SQL中：

想象一下一张桌子：

创建表A（F NVARCHAR（100），R1 INT，R2 INT，R3 INT）

F | R1 | R2| R3
A | 10 | 3 | 7
B | 5  | 4 | 6

我需要的结果集：

F | R1 | R2| R3
A | 10 | 3 | 7
B | 5  | 4 | 6
C | 15 | 7 | 13

其中C是A + B的结果，C是A和B之后的行

Answer 1

根据你的解释，我猜你需要总结所有行。

我想通过GROUP BY和ROLL UP，您可以设法获得正确的解决方案

尝试类似的东西：

SELECT F, SUM(R1), SUM(R2), SUM(R3)
FROM test
GROUP BY F WITH ROLLUP

Follow this link for a demo

更新：

我设法得到你在结果方面的要求： 试试这个（Works on SQL Server 2014）

SELECT F = ISNULL(F,'C'), SUM(R1) AS 'R1', SUM(R2) AS 'R2', SUM(R3) AS 'R3'
FROM test
GROUP BY F WITH ROLLUP

Follow this link for a demo

更新2（由Josh Gilfillan建议）：

上一个不管理需要为null的行。

SELECT CASE WHEN GROUPING(F) = 1 THEN 'C' ELSE F END AS 'F', SUM(R1) AS 'R1', SUM(R2) AS 'R2', SUM(R3) AS 'R3'
FROM test
GROUP BY F WITH ROLLUP

Link to the demo

Answer 2

SELECT * 
FROM A
WHERE F = 'A' OR F = 'B'
UNION ALL
SELECT 'C', 
(SELECT R1 FROM A WHERE F = 'A') + (SELECT R1 FROM A WHERE F = 'B'),
(SELECT R2 FROM A WHERE F = 'A') + (SELECT R2 FROM A WHERE F = 'B'),
(SELECT R3 FROM A WHERE F = 'A') + (SELECT R3 FROM A WHERE F = 'B')

DBFiddle