MATCH (ORG:ORG)-[ORGHASPROBLEM:HAS]->(PROBLEM:PROBLEM) WITH PROBLEM,
extract(NUM IN filter( V IN collect({ PROB1:PROBLEM.PROB_ID, PROB2:PROBLEM.REGION}) where V.PROB2= 'LONDON') | NUM.PROB1) AS MEASURES1,
extract(NUM IN filter( V IN collect({ PROB1:PROBLEM.PROB_ID, PROB2:PROBLEM.REGION}) where V.PROB2= 'PARIS') | NUM.PROB1) AS MEASURES2
unwind MEASURES1 AS RESULT1
unwind MEASURES2 AS RESULT2
RETURN DISTINCT PROBLEM.SLAB AS DIMENSION,count(RESULT1) AS MEASURES1,count(RESULT2) AS MEASURES2
我正在上传数据库的图像和预期的输出。任何人都可以重写查询或告诉我哪里出错了吗?
我的问题是MEASURES1和MEASURES2有我需要的数据。当我使用展开MEASURES1 AS RESULT1
时,它会根据需要提供输出,但如果是第二次展开(展开MEASURES2 AS RESULT2
),则会从MEASURES1
和MEASURES2
中删除整个数据
请参阅附图,更清楚地了解情景。
答案 0 :(得分:0)
以下查询将以允许您构建报告的方式从数据库中获取数据。作为奖励,如果您添加新区域,它也会起作用:
MATCH (p:PROBLEM)
WITH count(*) AS ct, p.REGION AS pregion, p.SLAB AS slab
RETURN slab, collect({region: pregion, count: ct}) as result;
希望这有帮助。
此致 汤姆