Question

我正在尝试将DB值分配给PHP变量。数据库是SQL。我希望数据库值为$ HaveOfficialPage。我怎么能这样做？

 $connection = mysqli_connect('localhost', '', '', '');

    if($connection){

        echo "Connected";

    }

    else {

        die("Database connection failed");

    }

    $query = "SELECT HaveOfficialPage FROM vf_Category";

        $result = mysqli_query($connection, $query);


    if(!$result){

        die("Query failed" . mysqli_error());
    }

Answer 1

如果你试图迭代结果：

while ($row = mysqli_fetch_row($result)) {
      $haveOfficialPage = $row[0];
    // do something with the variable
}

如果您只获得一条记录：

$row = mysqli_fetch_assoc($result);
$haveOfficialPage = $row["HaveOfficialPage"];

要选择具有条件的类别，请使用预准备语句

$paths = explode("/",$_SERVER["REQUEST_URI"]);
$category = end($paths);
$query = "SELECT HaveOfficialPage FROM vf_Category WHERE category_name = ?";
$stmt = mysqli_prepare($connection, $query);
mysqli_stmt_bind_param($stmt, "s", $category);

mysqli_stmt_bind_result($stmt, $haveOfficialPage); // here we assign the result to your variable
mysqli_stmt_fetch($stmt); // fetch

echo $haveOfficialPage;

如何将DB值分配给PHP变量？

1 个答案: