Question

我有一个Django模型，它有几个ForeignKey模型关系，我需要将它们组合成单个记录。

如果您查看下面的plaque模型，您会注意到我与veteran模型之间存在ForeignKey关系。我创建了一个没有真正思考它的老手模型，现在需要将老手字段添加到我的斑块模型中，但需要先导出所有数据，重建我的斑块模型，然后重新导入数据。

我已经安装了django-import-export，它适用于单个模型。我导出了我的牌匾数据，在退伍军人的领域，它只是添加了相关退伍军人的身份证号码。我想做的事情，如果可能的话，实际上是导出我的牌匾模型，而不是相关的退伍军人身份证号码，来自退伍军人模型的实际数据（first_name，last_name等）。我也在使用PostgreSQL，如果有帮助的话。有任何想法吗？谢谢。

class Plaque(models.Model):
     created_by = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE, related_name='plaques', default=1)
     group = models.ForeignKey(Group, blank=True, null=True, verbose_name='Group Name')
     veteran = models.ForeignKey(Veteran, blank=True, null=True)
     ...

更新 - 这是我的整个资源模型解决方案。这将导出一个文件，其中包含我所有ForeignKey模型字段的字符串值。

from import_export import resources, fields
from import_export.widgets import ForeignKeyWidget
from import_export.admin import ImportExportModelAdmin
from .models import Plaque, Group, Veteran, Service, Branch, War, Rank
from django.contrib import admin


class PlaqueResource(resources.ModelResource):
    vet_first = fields.Field(column_name='Veteran First', attribute='veteran', widget=ForeignKeyWidget(Veteran, field='first_name'))
    vet_middle = fields.Field(column_name='Veteran Middle', attribute='veteran', widget=ForeignKeyWidget(Veteran, field='middle_name'))
    vet_last = fields.Field(column_name='Veteran Last', attribute='veteran', widget=ForeignKeyWidget(Veteran, field='last_name'))
    vet_display = fields.Field(column_name='Veteran Display Name', attribute='veteran', widget=ForeignKeyWidget(Veteran, field='display_name'))
    vet_nick = fields.Field(column_name='Veteran Nickname', attribute='veteran', widget=ForeignKeyWidget(Veteran, field='nickname'))
    vet_bio = fields.Field(column_name='Veteran Biography', attribute='veteran', widget=ForeignKeyWidget(Veteran, field='biography'))
    vet_branch = fields.Field(column_name='Veteran Branch - service model', attribute='service', widget=ForeignKeyWidget(Service, field='branch'))
    vet_rank = fields.Field(column_name='Veteran Rank - service model', attribute='service', widget=ForeignKeyWidget(Service, field='rank'))
    vet_war = fields.Field(column_name='Veteran War - service model', attribute='service', widget=ForeignKeyWidget(Service, field='war'))
    vet_branch2 = fields.Field(column_name='Veteran Branch - branch model', attribute='service', widget=ForeignKeyWidget(Branch, field='branch'))
    vet_rank2 = fields.Field(column_name='Veteran Rank - rank model', attribute='service', widget=ForeignKeyWidget(Rank, field='rank'))
    vet_war2 = fields.Field(column_name='Veteran War - war model', attribute='service', widget=ForeignKeyWidget(War, field='war'))
    group_name = fields.Field(column_name='Group Name', attribute='group', widget=ForeignKeyWidget(Group, field='group_name'))
    group_type = fields.Field(column_name='Group Type', attribute='group', widget=ForeignKeyWidget(Group, field='group_type'))

    class Meta:
        model = Plaque

Answer 1

这应该有用，（from the docs）

# Or however your resources look
class PlaqueResource(resources.ModelResource):

    class Meta:
        model = Plaque
        fields = (<other_fields>, 'veteran__first_name', 'veteran__last_name',)

如何将包含ForeignKey模型关系的Django模型导出到组合文本文件中

1 个答案: