Question

if score <=30:
 print = "You have scored:" + score + ":("

else score > = 31 and < = 60
 print = "You have scored:" + score + ":/"

elif score < = 61
 print = "You have scored:" + score + ":)"

我正在python中进行测验，我需要它，以便当分数介于0-30,30-60和60+之间时，会显示不同的消息，尽管我尝试了上面的代码并且它一直说无效的语法

Answer 1

这是因为得分变量是一个整数，所以你不能那样打印它。试试这个，打印的东西应该放在括号中，而不是“=”。在if语句之后还应该有一个“：”。试试这个：

if score <=30:
     print("You have scored:" + str(score) + ":(")

elif score >= 31 and score <= 60:
     print("You have scored:" + str(score) + ":/")

elif score <= 61:
     print("You have scored:" + str(score) + ":)")

Answer 2

else score > = 31 and score <= 60

需要

elif score > = 31 and score <= 60:

你需要在最后一个elif上加:。而你的印刷陈述是错误的。语法为print 'hello'或print('hello')，具体取决于python版本。你应该看看初学python语法的东西

Python得分无效的语法不起作用

2 个答案: