两个逗号分隔的单元格与最终输出合并

Question

嘿所有我有以下SQL查询，我正在使用以从单元格中获取逗号分隔值：

WITH cte AS(
    SELECT        
        uT.id AS UID, 
        uT.employeeID, 
        uP.type, 
        pP.name 
    FROM 
        usersTbl AS uT
    CROSS APPLY 
        dbo.DelimitedSplit8K(uT.userPerms,',') AS uPcommaItems
    INNER JOIN 
        usersPermissions uP ON uP.id = uPcommaItems.Item
    CROSS APPLY 
        dbo.DelimitedSplit8K(uT.userPermPages,',') AS pPcommaItems
    INNER JOIN 
        pagePermissions pP ON pP.id = pPcommaItems.Item
)
SELECT DISTINCT 
    UID, 
    employeeID,
    STUFF(
            (
                SELECT 
                    ',' + stuff1.type
                FROM 
                    cte AS stuff1
                WHERE 
                    t.UID = stuff1.UID 
                FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)'), 1, 1, ''
          ) AS userPermissions,
    STUFF(
            (
                SELECT 
                    ',' + stuff2.type
                FROM 
                    cte AS stuff2
                WHERE 
                    t.UID = stuff2.UID
                FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)'), 1, 1, ''
          ) AS pagePermissions
FROM 
    cte AS t

userTbl 表格如下所示：

------------------------------------------------
ID    | employeeID | userPerms | pagePermPAges
------------------------------------------------
15    | 3FdFieu9I  | 1,3       | 1,4,5,6

userPermissions 表如下所示：

----------------
ID | type
----------------
1  | Read
2  | Write
3  | Upload
4  | Admin

这是我的 pagePermissions 表格如下：

ID | name
----------------
1  | bindex
2  | flight
3  | submit
4  | form
5  | information
6  | myPage
7  | register

上面查询的当前输出是：

-------------------------------------------------------------------------------------------------------
ID    | employeeID | userPermissions                         | pagePermissions
-------------------------------------------------------------------------------------------------------
15    | 3FdFieu9I  | Read,Read,Read...upload,upload,upload...| Read,Read,Read...upload,upload,upload...

应该读取此内容：

-------------------------------------------------------------------------
ID    | employeeID | userPermissions | pagePermissions
-------------------------------------------------------------------------
15    | 3FdFieu9I  | Read,Upload     | bindex,form,information,myPage

那里的任何MS SQL大师可以帮助我吗？

Answer 1

也许这可能会有所帮助

示例

Select A.ID
      ,A.employeeID
      ,usersPermissions = Stuff((Select Distinct ',' +[type] From userPermissions Where charindex(concat(',',ID,','),concat(',',A.[userPerms]    ,','))>0 For XML Path ('')),1,1,'') 
      ,pagePermissions = Stuff((Select Distinct ',' +[name] From pagePermissions Where charindex(concat(',',ID,','),concat(',',A.[userPermPages],','))>0 For XML Path ('')),1,1,'') 
 From usersTbl A

<强>返回

Answer 2

您只需获取权限的唯一值即可。您可以通过DISTINCT或GROUP BY到达那里。这是使用前一种方法修改的代码：

WITH cte AS(
    SELECT        
        uT.id AS UID, 
        uT.employeeID, 
        uP.type, 
        pP.name 
    FROM 
        usersTbl AS uT
    CROSS APPLY 
        dbo.DelimitedSplit8K(uT.userPerms,',') AS uPcommaItems
    INNER JOIN 
        usersPermissions uP ON uP.id = uPcommaItems.Item
    CROSS APPLY 
        dbo.DelimitedSplit8K(uT.userPermPages,',') AS pPcommaItems
    INNER JOIN 
        pagePermissions pP ON pP.id = pPcommaItems.Item
)
SELECT DISTINCT 
    UID, 
    employeeID,
    STUFF(
            (
                SELECT DISTINCT
                    ',' + stuff1.type
                FROM 
                    cte AS stuff1
                WHERE 
                    t.UID = stuff1.UID 
                FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)'), 1, 1, ''
          ) AS userPermissions,
    STUFF(
            (
                SELECT DISTINCT
                    ',' + stuff2.type
                FROM 
                    cte AS stuff2
                WHERE 
                    t.UID = stuff2.UID
                FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)'), 1, 1, ''
          ) AS pagePermissions
FROM 
    cte AS t

Answer 3

我认为应该这样做 如果你添加

Group by 

在For XML之前