未找到FROM关键字SQL中的预期错误

Question

我一直在通过电子邮件与我们的编码人员在另一个办公室工作，我们已经使用此代码了解了一下。每当我尝试执行查询时，我都会遇到oracle错误。以下是我正在使用的代码：

SELECT TALLY_TRAN_MSTR.SHIFT_DT, TALLY_TRAN_MSTR.LOGON_ID, TALLY_TRAN_MSTR.PRI_GRP_CD,
   SUM(case TALLY_TRAN_MSTR.PRI_GRP_CD
         WHEN 'PUT' THEN TALLY_TRAN_MSTR.FULL_PLLT_QTY
         ELSE 0
       END) AS Puts,
   SUM(TALLY_TRAN_MSTR.FULL_PLLT_QTY) AS SUM(TALLY_TRAN_MSTR.FULL_PLLT_QTY)
FROM   WBR_RW.TALLY_TRAN_MSTR
GROUP BY TALLY_TRAN_MSTR.SHIFT_DT, TALLY_TRAN_MSTR.LOGON_ID
HAVING ((Puts/(SUM(TALLY_TRAN_MSTR.FULL_PLLT_QTY))) > 0.75)
ORDER BY TALLY_TRAN_MSTR.SHIFT_DT, TALLY_TRAN_MSTR.LOGON_ID;

这有什么问题可能会导致错误吗？任何反馈都将不胜感激！

Answer 1

在这里利用一些甜蜜的甜蜜别名：

#include <iostream>
#include <string>
#include <cstring>

using namespace std;


int main()
{

    struct aboveAverage
    {
        string name9;
        double percentage1;
    };

    struct average
    {
        string name10;
        double percentage2;
    };

    struct belowAverage
    {
        string name11;
        double percentage3;
    };

    int numOfteams;
    double userInput;

    cout << "How many teams do you want to store? ";
    cin >> numOfteams;
    cin.get();

    aboveAverage * arrayOfAboveAverage = new aboveAverage[numOfteams];
    average * arrayOfAverage = new average[numOfteams];
    belowAverage * arrayOfbelowAverage = new belowAverage[numOfteams];

    for (int i = 0; i < numOfteams; i++)
    {
    start:
        int x = i + 1;
        string name5;
        cout << "Enter the name of the team " << x << ":";
        getline(cin, name5);

        cout << "Enter the team " << x << " percentage: ";
        cin >> userInput;
        cin.get();



        if (userInput >= 66 && userInput <= 100)
        {
            arrayOfAboveAverage[i].percentage1 = userInput;
            arrayOfAboveAverage[i].name9 = name5;
        }

        else if (userInput <= 66 && userInput >= 33)
        {
            arrayOfAverage[i].name10 = name5;
            arrayOfAverage[i].percentage2 = userInput;
        }
        else if (userInput <= 33 && userInput >= 0)
        {
            arrayOfbelowAverage[i].name11 = name5;
            arrayOfbelowAverage[i].percentage3 = userInput;
        }
        else
        {
            cout << "Percent cannot be greater than 100" << endl;
            goto start;
        }


    }

        cout << "Above Average :" << endl;
        for (int j = 0; j < numOfteams; j++)
        {
            if (arrayOfAboveAverage[j].percentage1 != NULL ||
                arrayOfAboveAverage[j].name9 != "")
            {
                cout << arrayOfAboveAverage[j].name9 <<" ";
                cout << arrayOfAboveAverage[j].percentage1 <<"%"<< endl;
            }
            else
            {
                cout << "None" << endl;
            }

        }

        cout << "Average :" << endl;
        for (int j = 0; j < numOfteams; j++)
        {
            if (arrayOfAverage[j].percentage2 > 0 ||
                arrayOfAverage[j].name10 != "")
            {
                cout << arrayOfAverage[j].name10 <<" ";
                cout << arrayOfAverage[j].percentage2 <<"%"<<endl;
            }
            else
            {
                cout << "None" << endl;
            }
        }

        cout << "Below Average : "<< endl;
        for (int k = 0; k < numOfteams; k++)
        {
            if (arrayOfbelowAverage[k].percentage3 > 0 || 
                arrayOfbelowAverage[k].name11 != "")
            {
                cout << arrayOfbelowAverage[k].name11 << " ";
                cout << arrayOfbelowAverage[k].percentage3 <<"%"<< endl;
            }
            else
            {

                cout << "None" << endl;
            }
        }

    delete[] arrayOfAboveAverage;
    delete[] arrayOfAverage;
    delete[] arrayOfbelowAverage;

    return 0;

}

了解这对您有何帮助。更改是最后一个列别名，SELECT T.SHIFT_DT, T.LOGIN_ID, T.PRI_GRP_CD, SUM(CASE WHEN T.PRI_GRP_CD = 'PUT' THEN T.FULL_PLLT_QTY ELSE 0 END) AS Puts, SUM(T.FULL_PLLT_QTY) AS SUM_PLLT_QTY FROM WBR_RW.TALLY_TRAN_MSTR AS T GROUP BY T.SHIFT_DT, T.LOGON_ID, T.PRI_GRP_CD HAVING (SUM(CASE WHEN T.PRI_GRP_CD = 'PUT' THEN T.FULL_PLLT_QTY ELSE 0 END) / SUM(T.FULL_PLLT_QTY)) > .75 ORDER BY T.SHIFT_DT, T.LOGON_ID; 子句是显式的。