Question

想象一下，你有一个包含字符串的listview和一个包含字符串的List。我想选择listview中与List<String>匹配的所有字符串，但是，我尝试使用SelectionModel中的selectIndices函数并输出正确的整数，但它不会选择它们，只会选择它们最后一个（灰色＆＃39; ish）颜色。我希望他们都有灰色的颜色。

一个例子是：

Listview: Cat, Dog, Tiger, Gorilla, Monkey
List: Dog & Gorilla.

选择Dog＆amp;列表视图中的大猩猩。 selectionMode是＆＃39; MULTIPLE＆＃39; SelectionModel是MultipleSelectionModel。

ObservableList<String> names = MainModel.getInstance().getGroupNames();
names.remove(group.getName());

listviewInheritance.setItems(names);

int[] indices = new int[group.getInheritance().size()];
List<String> inheriNames = group.getInheritance();

for(int i = 0; i < inheriNames.size(); i++) {
    for(int j = 0; j < names.size(); j++) {
        if(inheriNames.get(i).equals(names.get(j))) {
            System.out.println("Inheri: " + inheriNames.get(i) + " | Name: " + names.get(j)); // test purpose
            indices[i] = j;
        }
    }
}

if(indices.length > 0) {
    System.out.println(Arrays.toString(indices));
    listviewInheritance.getSelectionModel().selectIndices(-1, indices);
}

我错过了什么？

Answer 1

这是一个你可以改变的小应用程序。此应用会选择ListView中的任何List项。

import java.util.ArrayList;
import java.util.List;
import javafx.application.Application;
import javafx.collections.FXCollections;
import javafx.collections.ObservableList;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.ListView;
import javafx.scene.control.SelectionMode;
import javafx.scene.layout.StackPane;
import javafx.scene.layout.VBox;
import javafx.stage.Stage;

/**
 *
 * @author blj0011
 */
public class JavaFXApplication4 extends Application {



    @Override
    public void start(Stage primaryStage) {
        ListView lvMain = new ListView();//Create ListView  
        lvMain.getSelectionModel().setSelectionMode(SelectionMode.MULTIPLE);//Change ListView selection mode to multiple

        ObservableList<String> items = FXCollections.observableArrayList("Julia", "Ian", "Sue", "Matthew", "Hannah", "Stephan", "Denise");//ObseravableList that will be used to set the ListView
        lvMain.setItems(items);//Set the ListView's items

        List<String> list = new ArrayList();//List that will hold potential items that are in the ListView
        list.add("Sue");//Add Sue to List
        list.add("Stephan");//Add Stephan to List



        Button btn = new Button();
        btn.setText("Say 'Hello World'");
        btn.setOnAction(new EventHandler<ActionEvent>() {

            @Override
            public void handle(ActionEvent event) {

                //When the Button is pressed, loop through the list checking it's items against the ObservableList's items.
                for(String entry : list)
                {
                    for(String itemEntry : items)
                    {
                        if(entry.equals(itemEntry))//If the items are equal 
                        {
                            lvMain.getSelectionModel().select(itemEntry);//select the item in the ListView
                            break;//If you have duplicates in the ListView remove this line!
                        }
                    }
                }


            }
        });

        VBox vbox = new VBox();
        vbox.getChildren().addAll(lvMain, btn);


        StackPane root = new StackPane();
        root.getChildren().add(vbox);

        Scene scene = new Scene(root, 300, 250);

        primaryStage.setTitle("Hello World!");
        primaryStage.setScene(scene);
        primaryStage.show();
    }

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        launch(args);
    }

}

如果您希望所选项目在选中后显示为蓝色，则只需点击ListView，或者您可以在外部lvMain.requestFocus();之后添加For Loop。

Answer 2

我使用的代码确实有效，但我还有另一行覆盖它。然而，Sedrick Jefferson提到的requestFocus（）函数确实让它成为蓝色。感谢。

JavaFX Listview - 可选择多种选择

2 个答案: