Question

我正在努力调整数据库表中的重叠日期。示例数据如下

 StartDate  EndDate   UNIT  ID
2017-06-09  2017-06-22  1A  21
2017-06-09  2017-06-30  1B  21
2017-07-01  2017-07-31  1B  21

预期产出：

 StartDate  EndDate   UNIT  ID
2017-06-09  2017-06-22  1A  21
2017-06-22  2017-06-30  1B  21
2017-07-01  2017-07-31  1B  21

感谢您对此的帮助。

Answer 1

您可以在2012年以后使用领先/滞后，因为您使用的是2008，您可以查询如下：

;With cte as (
    Select *, RowN = Row_Number() over(partition by Id order by EndDate ) from #sampledata 
) 
Select StartDate = Coalesce (Case when Dateadd(DD, 1, c2.Enddate) = c1.Startdate then c1.Startdate Else c2.Enddate End, c1.StartDate)
        ,c1.Enddate, c1.Unit, C1.Id
    from cte c1 left join cte c2 
        on c1.RowN = c2.RowN+1

如果您仍然不想使用上述cte，那么您可以执行以下子查询：

Select StartDate = Coalesce (Case when Dateadd(DD, 1, c2.Enddate) = c1.Startdate then c1.Startdate Else c2.Enddate End, c1.StartDate)
        ,c1.Enddate, c1.Unit, C1.Id
    from (Select *, RowN = Row_Number() over(partition by Id order by EndDate ) from #sampledata ) c1 
    left join (Select *, RowN = Row_Number() over(partition by Id order by EndDate ) from #sampledata ) c2 
        on c1.RowN = c2.RowN+1

Answer 2

对@ Kannan的答案稍加修改。

Select StartDate = Coalesce (Case when c1.Startdate <= c2.Enddate
                                  then c2.Enddate 
                                  Else c1.Startdate 
                             End, 
                   c1.StartDate)
       ,c1.Enddate, c1.Unit, C1.Id
from
    (Select *, RowN = Row_Number() over(partition by Id order by EndDate ) 
     from #sample ) c1 
left join 
    (Select *, RowN = Row_Number() over(partition by Id order by EndDate ) 
     from #sample ) c2 
on c1.RowN = c2.RowN+1

无CTE调整重叠日期

2 个答案: