如何在Android中为Marshmallow打个电话按钮

时间:2017-08-15 13:12:59

标签: android android-phone-call

我正在尝试在Android中创建一个呼叫按钮。我创建了一个,它适用于所有类型的Android设备,但它不适用于Marshmallow。我不知道为什么。如何为Android Marshmallow创建一个调用按钮?

这是我用于调用按钮的代码:

public void button(View v) {

        String number = "12354656";
        Intent intent = new Intent(Intent.ACTION_CALL);
        intent.setData(Uri.parse("tel:" + number));


        if (ActivityCompat.checkSelfPermission(this, android.Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {

            return;
        }
        startActivity(intent);

}

3 个答案:

答案 0 :(得分:1)

该问题可能与Runtime Permissions中引入的Android 6.0有关。

你可以试试这个:

if (ContextCompat.checkSelfPermission(this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
    ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.CALL_PHONE},REQUEST_PHONE_CALL);
}
else
{
    startActivity(intent);
}

答案 1 :(得分:1)

您需要在手机设置中为您的应用启用权限。查看设置中的权限

答案 2 :(得分:0)

你必须尝试这个......

放入你的Android清单

<uses-permission android:name="android.permission.CALL_PHONE" />

获取拨打电话的运行时权限(Android API 23及以上版本)

private static final int REQUEST_PERMISSION_CALL = 111;

if (ContextCompat.checkSelfPermission(getActivity(),
                Manifest.permission.CALL_PHONE)
                != PackageManager.PERMISSION_GRANTED) {
            if (ActivityCompat.shouldShowRequestPermissionRationale(getActivity(),
                    Manifest.permission.CALL_PHONE)) {
                ActivityCompat.requestPermissions(this, getString(R.string.app_need_call_permission),
                        REQUEST_PERMISSION_CALL, Manifest.permission.CALL_PHONE);
            } else {
                ActivityCompat.requestPermissions(this, getString(R.string.app_need_call_permission),
                        REQUEST_PERMISSION_CALL, Manifest.permission.CALL_PHONE);
            }
        }

您将获得

的许可回复
@Override
    public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
        super.onRequestPermissionsResult(requestCode, permissions, grantResults);
        if (requestCode == REQUEST_PERMISSION_CALL) {
            // put your code here to make call
        }
    }

然后你必须拨打电话

Uri number = Uri.parse("tel:123456789");
Intent callIntent = new Intent(Intent.ACTION_DIAL, number);
startActivity(callIntent);

了解更多信息https://developer.android.com/training/permissions/requesting.html

希望这会对你有所帮助。