Question

您能帮我解决以下问题：

我有两张桌子

[sDocumentManagement]。[tDocuments]

[sDocumentManagement]。[tDocumentAttachments]

文档表中的每个条目都用于不同的文档，PK是DocumentID。在DocumentAttachments的表中，我们可以使用FK - DocumentID。

创建一个或多个附件

我想要实现的目标如下。

[
  {
    DocumentID: 1,
    Something: 'blb',
    Attachments: [
      {
        AttachmentID: 1,
        SomethingElse: '23232'
      }
    ]
  },
  {
    DocumentID: 2,
    Something: 'blb',
    Attachments: [
      {
        AttachmentID: 12,
        SomethingElse: '23232'
      },
      {
        AttachmentID: 13,
        SomethingElse: '23232'
      }
    ]
  }
]

我想从两个表中获取所有信息。

我尝试了以下查询

SELECT @DocumentsJSON = (
        SELECT *
        FROM [sDocumentManagement].[tDocuments]
        LEFT JOIN [sDocumentManagement].[tDocumentAttachments] ON [tDocuments].DocumentID = [tDocumentAttachments].DocumentID
    FOR JSON PATH
    )




   SELECT @DocumentsJSON = (
    SELECT
    (
        SELECT *
        FROM [sDocumentManagement].[tDocumentAttachments]
        WHERE [tDocumentAttachments].DocumentID = [tDocuments].DocumentID
        FOR JSON PATH
    ) Attachments
    , *
    FROM [sDocumentManagement].[tDocuments]
    FOR JSON PATH
    )

Answer 1

好的，我找到了解决方案：

SELECT @DocumentsJSON = (
       SELECT *,
       (
       SELECT * FROM [sDocumentManagement].[tDocumentAttachments] ATTACHMENTS
       WHERE ATTACHMENTS.DocumentID = DOCS.DocumentID
       FOR JSON AUTO
       ) DocumentAttachments
       FROM [sDocumentManagement].[tDocuments] DOCS
       WHERE DOCS.OrganizationID = @OrganizationID
       FOR JSON PATH, ROOT('Documents')
)

但还有另一个问题。

无论我宣布@DocumentsJSON NVarChar（MAX）输出， SQL只返回DocumentsJSON的4500个字符？知道问题在哪里吗？

如何使用SQL生成嵌套JSON

1 个答案: