将文件路径列表转换为树

Question

有一个如下所示的python文件路径列表：

file_path_list = ["test/dir1/log.txt", "test/dir1/dir2/server.txt", "test/manage/img.txt"]

我想将其转换为树。预期结果如下：

 tree_data = [
    {
      "path": "test",
      "children": [
        {
          "path": "dir1",
          "children": [
            {
              "path": "log.txt"
            },
            {
              "path": "dir2",
              "children": [
                {
                  "path": "server.txt"
                }
              ]
            }
          ]
        },
        {
          "path": "manage",
          "children": [
            {
              "path": "img.txt",
            }
          ]
        }
      ]
    }
  ]

转换的最佳方法是什么？

更新：我的代码在下面，但我认为它不太好。

    def list2tree(file_path):
        """Convert list to tree."""
        tree_data = [{
            "path": "root",
            "children": []
        }]
        for f in file_path:
            node_path = tree_data[0]
            pathes = f.split("/")
            for i, p in enumerate(pathes):
                length = len(node_path["children"])
                if not length or node_path["children"][length - 1]["path"] != p:
                    # create new node
                    new_node = {
                        "path": p,
                    }
                    if i != len(pathes) - 1:  # middle path
                        new_node["children"] = list()
                    node_path["children"].append(new_node)
                    node_path = new_node
                else:
                    node_path = node_path["children"][length - 1]
        return tree_data

我认为这种方式并不是最好的。有任何想法吗？非常感谢你！

Answer 1

一种方法是将字符串拆分为＆＃39; /＆＃39;并将它们放在默认值的默认值中，请参阅defaultdict of defaultdict, nested。