我正在向客户发送InlineQueryResultArticle
,并且我想知道如何获取所选结果及其数据(如result_id,...)。
这是发送结果的代码:
token = 'Bot token'
bot = telegram.Bot(token)
updater = Updater(token)
dispatcher = updater.dispatcher
def get_inline_results(bot, update):
query = update.inline_query.query
results = list()
results.append(InlineQueryResultArticle(id='1000',
title="Book 1",
description='Description of this book, author ...',
thumb_url='https://fakeimg.pl/100/?text=book%201',
input_message_content=InputTextMessageContent(
'chosen book:')))
results.append(InlineQueryResultArticle(id='1001',
title="Book 2",
description='Description of the book, author...',
thumb_url='https://fakeimg.pl/300/?text=book%202',
input_message_content=InputTextMessageContent(
'chosen book:')
))
update.inline_query.answer(results)
inline_query_handler = InlineQueryHandler(get_inline_results)
dispatcher.add_handler(inline_query_handler)
我正在寻找像on_inline_chosen(data)
这样的方法来获取所选项目的ID。 (上面的代码段1000 or 1001
),然后将相应的响应发送给用户。
答案 0 :(得分:4)
您应该在@BotFather中设置/setinlinefeedback
,然后您将获得此更新
答案 1 :(得分:2)
好的,我从here
得到了答案处理用户选择的结果:
from telegram.ext import ChosenInlineResultHandler
def on_result_chosen(bot, update):
print(update.to_dict())
result = update.chosen_inline_result
result_id = result.result_id
query = result.query
user = result.from_user.id
print(result_id)
print(user)
print(query)
print(result.inline_message_id)
bot.send_message(user, text='fetching book data with id:' + result_id)
result_chosen_handler = ChosenInlineResultHandler(on_result_chosen)
dispatcher.add_handler(result_chosen_handler)