Question

我有一个像这样的mysql查询....

   SELECT CAST(created_at AS DATE) as 'Created_Date', DAYNAME(CAST(created_at AS DATE)) as 'Day', sum(order_type_id=1) as 'Pickup', sum(order_type_id=2) as 'Delivery'
   FROM orders
   WHERE created_at >= curdate() - INTERVAL 7 DAY
   AND created_at < curdate()
   AND order_status_id != 3
   group by CAST(created_at AS DATE);

返回一些数据，如下所示

    Date   |      Day     | Pickup | Delivery
-----------------------------------------------
2017-08-08 |    Tuesday   |  02    |    01    
2017-08-09 |   Wednesday  |  01    |    01    
2017-08-10 |    Thursday  |  01    |    00  
2017-08-11 |    Friday    |  01    |    01   
2017-08-13 |    Sunday    |  01    |    00  
2017-08-14 |    Monday    |  01    |    01

我想要做的是在过去的7天内除了今天之前得到一些交货单和取货单的总结。

我的问题：如果您仔细观察上述情况，您会注意到我在2017-08-12（星期六）没有输出，因为在同一天没有完成任何操作。知道如何将这些空日期输入到我的输出中，所以我有类似下面的内容????

    Date   |      Day     | Pickup | Delivery
-----------------------------------------------
2017-08-08 |    Tuesday   |  02    |    01    
2017-08-09 |   Wednesday  |  01    |    01    
2017-08-10 |    Thursday  |  01    |    00  
2017-08-11 |    Friday    |  01    |    01   
2017-08-12 |   Saturday   |  00    |    00  
2017-08-13 |    Sunday    |  01    |    00  
2017-08-14 |    Monday    |  01    |    01

Answer 1

如果您确实拥有所有日期的数据（只是在该日期没有您想要的状态），那么您可以使用条件聚合：

   select CAST(created_at AS DATE) as Created_Date,
          DAYNAME(CAST(created_at AS DATE)) as Day,
          sum(order_type_id = 1 and order_status_id <> 3) as Pickup,
          sum(order_type_id = 2 and order_status_id <> 3) as Delivery
   from orders
   where created_at >= curdate() - INTERVAL 7 DAY AND created_at < curdate()
   group by CAST(created_at AS DATE);

如果不是这种情况，那么您需要一个每个日期都有一行的表。最简单的方法是日历表。

Answer 2

你可以尝试用你喜欢的方式加入你的选择。

RIGHT JOIN (
select curdate() as `date`    union
select DATE_SUB(curdate(), INTERVAL 1 day) as `date` union
select DATE_SUB(curdate(), INTERVAL 2 day) as `date` union
select DATE_SUB(curdate(), INTERVAL 3 day) as `date` union
select DATE_SUB(curdate(), INTERVAL 4 day) as `date` union
select DATE_SUB(curdate(), INTERVAL 5 day) as `date` union
select DATE_SUB(curdate(), INTERVAL 6 day) as `date`
) as dates

在mysql数据集中添加缺少日期

2 个答案: