Question

我的Web API方法要么返回包含多个文件的单个文件或zip文件。这是Web API实现。

        public HttpResponseMessage Download([FromUri] List<string> fileNames)
        {
            try
            {
                HttpResponseMessage result = new HttpResponseMessage(HttpStatusCode.OK);
                if (fileNames.Count > 1)
                {
                    List<string> filePaths = new List<string>();
                    
                    MemoryStream memoryStreamOfFile = new MemoryStream();

                    using (ZipFile zip = new ZipFile())
                    {
                        foreach (var fileName in fileNames)
                        {
                            zip.AddFile(HttpRuntime.AppDomainAppPath + @"\Uploaded\" + fileName);
                        }
                        zip.Save(memoryStreamOfFile);
                        memoryStreamOfFile.Seek(0, SeekOrigin.Begin);
                        result.Content = new StreamContent(memoryStreamOfFile);
                        result.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
                        result.Content.Headers.ContentDisposition.FileName = "files.zip";
                        result.Content.Headers.ContentType =
                            new MediaTypeHeaderValue("application/octet-stream");
                        return result;
                    }
                }

                if (!string.IsNullOrEmpty(fileNames[0]))
                {
                    string filePath = HttpRuntime.AppDomainAppPath + @"\Uploaded\" + fileNames[0];
                    
                    var stream = new FileStream(filePath, FileMode.Open, FileAccess.Read);
                    result.Content = new StreamContent(stream);
                    result.Content.Headers.ContentType =
                        new MediaTypeHeaderValue("application/octet-stream");
                    return result;
                }
                return this.Request.CreateResponse(HttpStatusCode.NotFound, "File not found.");
            }
            catch (Exception ex)
            {
                return this.Request.CreateResponse(HttpStatusCode.InternalServerError, ex);
            }
        }

这种方法工作正常，我敢肯定，因为当我通过“高级休息客户端”请求此方法时，Google Chrome扩展程序文件会被下载并完美运行。

但是当我通过Angularjs服务调用请求此方法时，文件无法打开。图像文件给我以下错误

关注PDF

并关注zip

预计会出现Advance Rest Client行为，但不会出现Angularjs行为。以下是我的角色代码

"download": {
        method: "GET",
        url: "api/files/Download/",
        params: { fileNames: "@fileNames" },
        responseType: "arraybuffer",
        headers: {
            'Content-Type': "application/octet-stream"
        }
 }

return fileManagerClientService.download({ fileNames: fileName })
                .$promise
                .then(function (data) {
                    
                    console.log(data);
                    appInfo.setInfo({ message: "files downloaded successfully" });

                    try {
                        var blob = new Blob([data]);

                        if (typeof (fileName) == "string")
                            FileSaver.saveAs(blob, fileName);
                        else
                            FileSaver.saveAs(blob, "AllFiles.zip");

                    } catch (ex) {
                        console.log(ex);
                    }
                },

请告诉我在Angular方面我缺少什么？我尝试了很多代码片段，但它们没有用！

Answer 1

所以小伙子们，通过用$ http调用替换$ resource解决了这个问题。这是工作代码，

function download(fileName) {
            appInfo.setInfo({ busy: true, message: "loading files" });
            

            return $http({
                method: "GET",
                url: "api/files/Download/",
                params: { fileNames: fileName },
                responseType: "arraybuffer"
            }).then(function (data) {
                appInfo.setInfo({ message: "files downloaded successfully" });

                try {
                    var blob = new Blob([data.data]);

                    if (typeof (fileName) == "string")
                        FileSaver.saveAs(blob, fileName);
                    else
                        FileSaver.saveAs(blob, "AllFiles.zip");

                } catch (ex) {
                    console.log(ex);
                }
            }, function (error) {

            });
        }

这是正常工作的代码，我希望有人能够使用$ resource获得更好的解决方案，以及为什么它无法使用$ resource。

Angularjs中下载的文件无法正常保存

1 个答案: