Question

如何从viewmodel访问PasswordValidator属性以装饰输入密码验证？

例如，这是在IdentityConfig.cs / Create

中

        // Configure validation logic for passwords
        manager.PasswordValidator = new PasswordValidator
        {
            RequiredLength = 7,
            RequireNonLetterOrDigit = false,
            RequireDigit = true,
            RequireLowercase = false,
            RequireUppercase = false,
        };

然后在AccountViewModels.cs

中

public class RegisterViewModel
{
    [Required]
    [EmailAddress]
    [Display(Name = "Email")]
    public string Email { get; set; }

    [Required]
    [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 6)]
    [DataType(DataType.Password)]
    [Display(Name = "Password")]
    public string Password { get; set; }

    [DataType(DataType.Password)]
    [Display(Name = "Confirm password")]
    [Compare("Password", ErrorMessage = "The password and confirmation password do not match.")]
    public string ConfirmPassword { get; set; }
}

在密码输入长度正确之前，属性[StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 7)]会阻止提交表单。如果我删除它，表单可能会被发布但由于PassordValidator会产生错误，所以我认为最好有这个属性，所以在正确之前不能发布任何内容。

如何访问RegisterViewModel中的PasswordValidator属性？

例如

[StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = passwordValidator.RequiredLength)]

Answer 1

可能有更好的方法，但考虑到您希望在passwordvalidator和viewmodel之间共享配置并使它们保持同步，您可以使用应用程序设置来外部化配置，这样可以使两个类保持分离。 / p>

所以你可以在web.config中添加appsetting（如果使用.NET Core，则为appsettings.json）

示例（伪代码，未检查它编译但显示了想法）

的web.config：

<appSettings>
  <add key="passwordminlength" value="6" />
...
</appSettings>

属性：

[StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = (int) ConfigurationManager.AppSettings["passwordminlength")]

验证

manager.PasswordValidator = new PasswordValidator
{
   RequiredLength = (int) ConfigurationManager.AppSettings["passwordminlength")
   ...
}

访问数据注释错误消息中的PasswordValidator

1 个答案: