Question

我在swift 3中解析json数据。这是结果的结构。我需要将这个括号内容分开并将它们放入一个数组中。

 (
    { 
        name:"devin,patrick";
    }
       ,

   {
        name:"devin,kalvin";
   }
      ,

   {
       name: "devin,nic";
   }

)

这是代码，

 //parsing json data

                if let jsonparsed = content as? NSDictionary {

                    if let neededData = jsonparsed["data"] {

                        print(neededData)

                        let exactData = String(describing:neededData)
                 let gotData = exactData.components(separatedBy: ",")



                    }
                }

我将数据转换为字符串并尝试用逗号分隔内容，因为名称也有逗号，所以它不能正常工作，我需要将逗号覆盖的内容分开，任何帮助都会很棒。

Answer 1

序列化你的json字符串后，获取一个Dictionary列表，获取每个字典的名称，然后执行componentsSeparatedBy你得到每个名字

   if let data = text.data(using: .utf8) ,
        let dict = try? JSONSerialization.jsonObject(with: data, options: []) as? [String: String]{

        let array = dict.flatMap({$0["name"]}) //return ["devin,patrick", "devin,kalvin", "devin,nic"]
        let names = array.flatMap({$0.components(separatedBy: ",")}) //return ["devin" ,"patrick" ,"devin" ,"kalvin" ,"devin" ,"nic"]
        let uniqueNames = Set(names) // return ["nic", "patrick", "devin", "kalvin"]
    }

单独用逗号分隔的json内容

1 个答案: