Question

我有两张表Sales和Charges。

表格数据为：

  'Sales'                                     'Charges'
SID    F_AMT                           SID            C_AMT
1       100                            1               10
1       100                            1               10
1       100                            1               20
1       200                            2               20
2       200                            2               10
2       300                            3               20
4       300                            3               30
4       300                            3               10
4       300                            5               20
4       200                            5               10

我想要输出如下：

SID       Total_Fees     Total_charges
1           500              40
2           500              30
3            0               60
4           1100             0
5            0               30

Answer 1

假设您想要为整个表格执行此操作，这是最简单的方法：

Select Sid
            , Sum(f_amt) as total_fees
            , Sum(c_amt) as total_charges
From ( select sid, f_amt, 0 as c_amt
              From sales
              Union all
              select sid, 0 as f_amt, c_amt
              From charges
          )
Group by sid

Answer 2

使用full join和nvl()：

select sid, nvl(sum(f_amt), 0) fees, nvl(sum(c_amt), 0) charges
  from sales s 
  full join charges c using (sid)
  group by sid 
  order by sid

演示：

with sales(sid, f_amt) as (
    select 1, 100 from dual union all select 1, 100 from dual union all 
    select 1, 100 from dual union all select 1, 200 from dual union all 
    select 2, 200 from dual union all select 2, 300 from dual union all 
    select 4, 300 from dual union all select 4, 300 from dual union all 
    select 4, 300 from dual union all select 4, 200 from dual ),
charges (sid, c_amt) as (
    select 1, 10 from dual union all select 1, 10 from dual union all
    select 1, 20 from dual union all select 2, 20 from dual union all
    select 2, 10 from dual union all select 3, 20 from dual union all
    select 3, 30 from dual union all select 3, 10 from dual union all
    select 5, 20 from dual union all select 5, 10 from dual )
select sid, nvl(sum(f_amt), 0) fees, nvl(sum(c_amt), 0) charges
  from sales s 
  full join charges c using (sid)
  group by sid 
  order by sid

输出：

   SID       FEES    CHARGES
------ ---------- ----------
     1       1500        160
     2       1000         60
     3          0         60
     4       1100          0
     5          0         30

Answer 3

您可以使用条件聚合：

SELECT SID,
      COALESCE(SUM(CASE WHEN t=1 THEN AMT END),0) AS Total_Fees,
      COALESCE(SUM(CASE WHEN t=2 THEN AMT END),0) AS Total_Charges
FROM (SELECT SID, F_AMT AS AMT, 1 AS t
      FROM Sales
      UNION ALL
      SELECT SID, C_AMT AS AMT, 2 AS t
      FROM Charges) sub
GROUP BY SID
ORDER BY SID;

<强> DB Fiddle Demo

如何将两个表中的两个不同字段与一个字段相加是很常见的

3 个答案: