Question

我有三个表，一个是product，第二个是appliedFeaturesValue，第三个是appliedFeatures

在Product表中，applyFeaturesValue具有ManyToMany关系。

ProductID appliedFeaturesValueId
 1          1
 1          2
 2          1
 3          2

并且在appliedFeaturesValue表中与appliedFeatures具有ManyToOne关系。

appliedFeaturesValue    appliedFeaturesId
    1                          70
    2                          88

我想得到产品ID 1，其中appliedFeaturesValue Id 1和2都代表appliedFeaturesId 70和88。

如果我正在使用IN子句，则不会返回确切的产品数据，其中appliedFeaturesValue.id = 1 AND appliedFeaturesValue.id = 2.

如果我使用AND子句，则找不到结果。

这是我使用AND子句的原始查询，其中找不到结果： -

SELECT p0_ FROM Product p0_ INNER JOIN product_applied_features_value p2_ ON p0_.id = p2_.product_id INNER JOIN applied_features_value a1_ ON a1_.id = p2_.applied_features_value_id WHERE p0_.status = 1 AND a1_.applied_features_id = 70 AND a1_.applied_features_id = 88 ORDER BY p0_.id DESC

这是我使用IN子句的查询： -

SELECT p0_ FROM Product p0_ INNER JOIN product_applied_features_value p2_ ON p0_.id = p2_.product_id INNER JOIN applied_features_value a1_ ON a1_.id = p2_.applied_features_value_id WHERE p0_.status = 1 AND a1_.applied_features_id IN (70,88) ORDER BY p0_.id DESC

我将如何获得完全匹配的记录？

Answer 1

尝试以下查询，这可以帮助您。

SELECT product.* FROM Product product 
INNER JOIN product_applied_features_value prodAppFeatures ON product.appliedFeaturesValueId = prodAppFeatures.id
INNER JOIN applied_features_value appFeatures ON appFeatures.id = prodAppFeatures.applied_features_value_id 
WHERE product.status = 1 AND 
    appFeatures.applied_features_id = 70 AND a1_.applied_features_id = 88 ORDER BY product.id DESC

mysql查询ManyToMany Relation

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