Question

尝试将XML反序列化为对象时遇到问题，我收到了错误消息

"There is an error in XML document (2, 2)."

使用innerException：

"<string xmlns='http://tempuri.org/'> was not expected."

我在这些链接中尝试了解决方案： Error Deserializing Xml to Object - xmlns='' was not expected，xmlns=''> was not expected. - There is an error in XML document (2, 2) while DeserializeXml to object

但仍未解决我的问题..

这是我的代码：

    bulk_response result = ConvertXMLString.convertXMLStringToObject<bulk_response>(response);

这是我的反序列化代码：

public static T convertXMLStringToObject<T>(string input) where T : class
        {
            try
            {
                System.Xml.Serialization.XmlSerializer ser = new System.Xml.Serialization.XmlSerializer(typeof(T));

                using (StringReader sr = new StringReader(input))
                {
                    return (T)ser.Deserialize(sr);
                    sr.Close();
                }
            }
            catch (Exception ex)
            {
                return null;
            }
        }

这是我的班级：

  public class bulk_response
    {
        public string status_code { get; set; }
        public string status_text { get; set; }
        public string transaction_id { get; set; }
    }

我找不到的问题是什么？

更新：这是我从http post响应中得到的xml：

<?xml version="1.0" encoding="utf-8"?>
<string xmlns="http://tempuri.org/"><?xml version="1.0" encoding="utf-16"?>
<bulk_response xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <status_code>hansen</status_code>
  <status_text>angie</status_text>
  <transaction_id>ini testing aja</transaction_id>
</bulk_response></string>

这就是我通过http post传递数据并获得响应的方式：

HttpWebRequest httpReq = (HttpWebRequest)WebRequest.Create(destinationUrl);
// add the parameters as key valued pairs making
// sure they are URL encoded where needed
ASCIIEncoding encoding = new ASCIIEncoding();
byte[] postData = encoding.GetBytes(param);
httpReq.ContentType = "application/x-www-form-urlencoded";
httpReq.Method = "POST";
httpReq.ContentLength = postData.Length;
// convert the request to a steeam object and send it on its way
Stream ReqStrm = httpReq.GetRequestStream();
ReqStrm.Write(postData, 0, postData.Length);
ReqStrm.Close();
// get the response from the web server and
// read it all back into a string variable
HttpWebResponse httpResp = (HttpWebResponse)httpReq.GetResponse();
StreamReader respStrm = new StreamReader(
httpResp.GetResponseStream());
string result = respStrm.ReadToEnd();
httpResp.Close();
respStrm.Close();

return result;

Answer 1

如何序列化XML？它看起来很混乱。

<?xml ...标记后面的附加<string>对我来说很奇怪。我从未见过这个。这是有效的XML吗？
当您从XML反序列化对象时，序列化程序会根据类来指定要命名的根节点。这就是<string> was not expected.的意思 - 它期望bulk_response - 代替
status_text的结束标记不是结束标记，应为<status_text>angie</status_text>
在不同级别上定义xmlns也很少见（如果它是合法的XML） - 但我不明白为什么你需要它们，你可以留下它们

说完之后，将XML简化为

<?xml version="1.0" encoding="utf-8"?>
<bulk_response>
  <status_code>hansen</status_code>
  <status_text>angie</status_text>
  <transaction_id>ini testing aja</transaction_id>
</bulk_response>

你的代码就像一个魅力。问题似乎不是反序列化代码，而是服务器端的序列化代码。

将Xml反序列化为对象时出错 - {<string xmlns =“http://tempuri.org/”>未被预期。}

1 个答案: