Question

你好试着找到数组中的重复值我有这样的数组

所以我想在%之后找到重复的foreach($array as $value){ $s = explode('%',$value); if($s[1] == $s[1]){ echo 'there are duplicated 2'; } }所以我在foreach中使用了爆炸

$s[1]

所以我希望%检查数组中const key1 = 'hello'; const key2 = 'world'; type _MyInterface = Record<typeof key1, {}> & Record<typeof key2, string>; interface MyInterface extends _MyInterface { } var _myObject = {} as MyInterface; _myObject[key1] = { something: 'something' }; _myObject[key2] = 'some other things'; const myObject = _myObject;之后的值是否重复无论如何都要这样做

Answer 1

您需要在循环浏览时收集右侧值并检查重复项。我通过“偏移”[2]访问字符串的右侧值。找到后，您可以使用break退出循环。

代码：（Demo）

$array=['1%2','3%4','1%2','1%3'];
$kept=[];
foreach($array as $i=>$v){
    if(in_array($v[2],$kept)){
        echo "Element (index $i) containing $v has duplicate right side value.";
        break;
    }
    $kept[]=$v[2];
}

输出：

Element (index 2) containing 1%2 has duplicate right side value.

如果您要搜索以%2结尾的所有元素，可以使用preg_grep()。

代码：

$search=2;
$array=['1%2','1%3','1%4','3%2','5%2'];
var_export(preg_grep("/%{$search}$/",$array));

输出：

array (
  0 => '1%2',
  3 => '3%2',
  4 => '5%2',
)

或者没有正则表达式，它将需要更多函数调用：

$search=2;
$array=['21%2','1%3','2%22','1%4','3%21','5%2'];
var_export(array_filter($array,function($v)use($search){return strpos($v,"%$search")+2===strlen($v);}));

输出：

array (
  0 => '21%2',
  5 => '5%2',
)

... [深呼吸]尝试回答＃4 ......

代码：

$array=['1%2','1%3','1%4','3%2','5%2'];
foreach($array as $v){
    $grouped[explode('%',$v)[1]][]=$v;  // use right side number as key
}
var_export($grouped);

输出：

array (
  2 => 
  array (
    0 => '1%2',
    1 => '3%2',
    2 => '5%2',
  ),
  3 => 
  array (
    0 => '1%3',
  ),
  4 => 
  array (
    0 => '1%4',
  ),
)

如果要计算数组中的右侧值：

$array=['1%2','1%3','1%4','3%2','5%2'];
$array=preg_replace('/\d+%/','',$array);  // strip the left-size and % from elements
var_export(array_count_values($array));  // count occurrences

输出：

// [right side values] => [counts]
array (
  2 => 3,
  3 => 1,
  4 => 1,
)

检查数组中的值是否与另一个爆炸值重复

1 个答案: