将元素添加到Python列表时的“AttributeError”

时间:2017-08-14 02:43:15

标签: python list append

我是python的新手,我在保存重命名文件列表时遇到问题,因此我最终可以将文件移动到新目录。我的代码发布在下面:

import os
new_files = []

        for orig_name in orig:           #This loop splits each file name into a list of stings containing each word
            if '.' in orig_name:            #This makes sure folder names are not changed, only file names
                base = os.path.splitext(orig_name)[0]
                ext = os.path.splitext(orig_name)[1]
                sep = base.split()             #Separation is done by a space
                for t in sep:           #Loops across each list of strings into an if statement that saves each part to a specific variable
                    if t.isalpha() and len(t) == 3:
                        wc = t
                        wc = wc.upper()
                    elif len(t) > 3 and len(t) < 6:
                        wc = t
                        wc = wc.upper()
                    elif len(t) >= 4:
                        pnum = t
                        if pnum.isalnum:
                            pnum = pnum.upper()
                    elif t.isdecimal() and len(t) < 4:
                        opn = t
                        if len(opn) == 2:
                            opn = '0' + opn
                    else:
                        pass
                new_nam = '%s OP %s %s' % (pnum, opn, wc)          #This is the variable that contain the text for the new name
                new_nam = new_nam + ext
                new_files = new_files.append(new_nam)
                print(new_files)

基本上,此代码的作用是循环原始文件名(orig),并将它们重命名为特定约定(new_name)。我遇到的问题是每次迭代,我试图将每个new_nam保存到列表“new_files”但是我一直收到这个错误:

line 83, in <module>
    new_files = new_files.append(new_nam)
AttributeError: 'NoneType' object has no attribute 'append'

基本上我认为你不能在一个有意义的列表中添加“无类型”,但是当我打印所有的new_nam时,它们都是不是None类型的字符串。所以我想我不知道为什么这段代码没有将每个新文件名添加到new_files列表中。非常感谢任何建议的建议,无法想出这一点:/谢谢!

1 个答案:

答案 0 :(得分:2)

list.append inplace 操作。您必须在不指定返回值的情况下调用该函数:

In [122]: data = [1, 2, 3]

In [123]: data.append(12345)

In [124]: data
Out[124]: [1, 2, 3, 12345]

在您的情况下,您需要

new_files.append(new_nam)

list docs中描述的所有list.___方法都已到位。