I am creating a word game application , I have created a grid view consisting of buttons. When I click a button in the grid view a popup windows opens which contains all the English alphabets.Now when I click any letter in my pop up window , I want that letter to appear in my grid that is the string in my pop window's button must appear in my grid view's button. , how do I do it?
This is my button's code:
button1.setOnClickListener(new View.OnClickListener()
{
@Override
public void onClick(View v) {
layoutInflater = (LayoutInflater) getApplicationContext().getSystemService(LAYOUT_INFLATER_SERVICE);
View container = layoutInflater.inflate(R.layout.activity_popup,null);
popupWindow = new PopupWindow(container,800,1100,true);
popupWindow.showAtLocation(constraintLayout, Gravity.NO_GRAVITY,150,400);
b1=(Button) findViewById(R.id.b1);
String s1 = b1.getText().toString();
button1.setText(s1);
container.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View view, MotionEvent motionevent){
popupWindow.dismiss();
return true;
}
});
}
});
My popup window's code:
b1.setOnClickListener(new View.OnClickListener()
{
@Override
public void onClick(View v)
{
String s1 = "A";
overridePendingTransition(android.R.anim.fade_in, android.R.anim.fade_out);
finish();
}
});
Screenshots of the app
This is my grid layout where the user must enter the letters
When I click any button on the grid this is the pop up window which is displayed.
If I run this , the app is getting stopped.
答案 0 :(得分:0)
b1
is a button contained in your activity_popup
- layout. So you might want to try b1 = (Button) container.findViewById(R.id.b1)
instead. If thats not working, post your exception!