只要用户输入" house"在edittext中。这就是我所做的:
if (textA.getText().toString().equals("house")){
String name = String.valueOf(textA.getText().toString().equals("house"));
name.setTextColor(Color.parseColor("#bdbdbd"));
}
我的xml如下
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginRight="15dp"
android:layout_marginEnd="15dp"
android:orientation="vertical"
android:padding="5dp">
<EditText
android:id="@+id/textA"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="5dp"
android:inputType="textMultiLine"
android:maxLines ="4"
android:maxLength ="2000"
android:textColorHint="@color/grey"
android:background="@android:color/transparent"
android:gravity="top"/>
</LinearLayout>
然而这导致应用程序崩溃。不知道我做错了什么。我是android的新手。有什么建议吗?
答案 0 :(得分:1)
您必须编写如下代码
textA.addTextChangedListener(new TextWatcher() { @Override public void afterTextChanged(Editable s) {} @Override public void
beforeTextChanged(CharSequence s, int start, int count, int after) { }
@Override public void onTextChanged(CharSequence s, int start, int
before, int count) {
if(s.length() != 0 && s.contains("home")) name.setTextColor(Color.parseColor("#bdbdbd"));
});
答案 1 :(得分:1)
这对我有用
textA.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
String str="home";
Spannable spannable =textA.getText();
if(s.length() != 0) {
textA.setTextColor(Color.parseColor("#0000FF"));
ForegroundColorSpan fcs = new ForegroundColorSpan( Color.GREEN);
String s1 = s.toString();
int in=0; // start searching from 0 index
// keeps on searching unless there is no more function string found
while ((in = s1.indexOf(str,in)) >= 0) {
spannable.setSpan(
fcs,
in,
in + str.length(),
Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
// update the index for next search with length
in += str.length();
}
}
}
@Override
public void afterTextChanged(Editable s) {
}
});
答案 2 :(得分:0)
等于返回值是布尔值。 所以你必须改变它。
public boolean equals(Object anObject)
if (textA.getText().toString().equals("house")){
textA.setTextColor(Color.parseColor("#bdbdbd"));
}