如何将手机通讯录中的电话号码3456781276显示在listview的最顶部，然后是正常情况下的所有其他联系人？我相信我将这个值传递到我的自定义适配器和我的getView()，但根本不知道如何继续。你能帮忙吗？
在我的ListView中，我使用以下代码显示所有手机通讯录：
class LoadContact extends AsyncTask<Void, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected Void doInBackground(Void... voids) {
// we want to delete the old selectContacts from the listview when the Activity loads
// because it may need to be updated and we want the user to see the updated listview,
// like if the user adds new names and numbers to their phone contacts.
selectPhoneContacts.clear();
// we have this here to avoid cursor errors
if (cursor != null) {
cursor.moveToFirst();
}
try {
// get a handle on the Content Resolver, so we can query the provider,
cursor = getApplicationContext().getContentResolver()
// the table to query
.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
null,
null,
// display in ascending order
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " COLLATE LOCALIZED ASC");
// get the column number of the Contact_ID column, make it an integer.
// I think having it stored as a number makes for faster operations later on.
// get the column number of the DISPLAY_NAME column
int nameIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
// get the column number of the NUMBER column
int phoneNumberofContactIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
cursor.moveToFirst();
// We make a new Hashset to hold all our contact_ids, including duplicates, if they come up
Set<String> ids = new HashSet<>();
do {
System.out.println("=====>in while");
// get a handle on the display name, which is a string
name = cursor.getString(nameIdx);
// get a handle on the phone number, which is a string
phoneNumberofContact = cursor.getString(phoneNumberofContactIdx);
//----------------------------------------------------------
// get a handle on the phone number of contact, which is a string. Loop through all the phone numbers
// if our Hashset doesn't already contain the phone number string,
// then add it to the hashset
if (!ids.contains(phoneNumberofContact)) {
ids.add(phoneNumberofContact);
System.out.println(" Name--->" + name);
System.out.println(" Phone number of contact--->" + phoneNumberofContact);
SelectPhoneContact selectContact = new SelectPhoneContact();
selectContact.setName(name);
selectContact.setPhone(phoneNumberofContact);
selectPhoneContacts.add(selectContact);
}
} while (cursor.moveToNext());
} catch (Exception e) {
Toast.makeText(NewContact.this, "what the...", Toast.LENGTH_LONG).show();
e.printStackTrace();
// cursor.close();
} finally {
}
if (cursor != null) {
cursor.close();
}
return null;
}
@Override
protected void onPostExecute(Void aVoid) {
super.onPostExecute(aVoid);
adapter = new SelectPhoneContactAdapter(selectPhoneContacts, NewContact.this);
// we need to notify the listview that changes may have been made on
// the background thread, doInBackground, like adding or deleting contacts,
// and these changes need to be reflected visibly in the listview. It works
// in conjunction with selectContacts.clear()
adapter.notifyDataSetChanged();
listView.setAdapter(adapter);
//this function measures the height of the listview, with all the contacts, and loads it to be that
//size. We need to do this because there's a problem with a listview in a scrollview.
justifyListViewHeightBasedOnChildren(listView);
}
}
我的模特，吸气鬼和制定者，就像：
public class SelectPhoneContact {
String phone;
public String getPhone() {return phone;}
public void setPhone(String phone) {
this.phone = phone;
}
String name;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
我的自定义适配器：
public class SelectPhoneContactAdapter extends BaseAdapter {
//define a list made out of SelectContacts and call it theContactsList
public List<SelectPhoneContact> theContactsList;
//define an array list made out of SelectContacts and call it arraylist
private ArrayList<SelectPhoneContact> arraylist;
Context _c;
//define a ViewHolder to hold our name and number info, instead of constantly querying
// findviewbyid. Makes the ListView run smoother
ViewHolder v;
public SelectPhoneContactAdapter(List<SelectPhoneContact> selectPhoneContacts, Context context) {
theContactsList = selectPhoneContacts;
_c = context;
this.arraylist = new ArrayList<SelectPhoneContact>();
this.arraylist.addAll(theContactsList);
Collections.sort(this.arraylist, new Comparator<SelectPhoneContact>() {
@Override
public int compare(SelectPhoneContact t1, SelectPhoneContact t2) {
if(t2.getPhone().equals ("3456781276")) { // put the phone number you want on top here
return 1;
} else {
return t1.getName().compareTo(t2.getName());
}
}
});
}
@Override
public int getCount() {
return arraylist.size();
}
@Override
public Object getItem(int i) {
return arraylist.get(i);
}
@Override
public long getItemId(int i) {
return i;
}
@TargetApi(Build.VERSION_CODES.LOLLIPOP)
static class ViewHolder {
// In each cell in the listview show the items you want to have
// Having a ViewHolder caches our ids, instead of having to call and load each one again and again
CheckBox checkbox;
TextView title, phone, lookup;
// CheckBox check;
}
@Override
public View getView(int i, View convertView, ViewGroup viewGroup) {
//we're naming our convertView as view
View view = convertView;
if (view == null) {
//if there is nothing there (if it's null) inflate the layout for each row
LayoutInflater li = (LayoutInflater) _c.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
view = li.inflate(R.layout.phone_inflate_listview, null);
//or else use the view (what we can see in each row) that is already there
} else {
view = convertView;
}
v = new ViewHolder();
// So, for example, title is cast to the name id, in phone_inflate_listview,
// phone is cast to the id called no etc
v.title = (TextView) view.findViewById(R.id.name);
// v.check = (CheckBox) view.findViewById(R.id.check);
v.phone = (TextView) view.findViewById(R.id.no);
// store the holder with the view
final SelectPhoneContact data = (SelectPhoneContact) arraylist.get(i);
v.title.setText(data.getName());
v.phone.setText(data.getPhone());
view.setTag(data);
return view;
}
}
答案 0 :(得分：2)
尝试修改适配器的构造函数，如下所示：
public SelectPhoneContactAdapter(List<SelectPhoneContact> selectPhoneContacts, Context context) {
theContactsList = selectPhoneContacts;
_c = context;
this.arraylist = new ArrayList<SelectPhoneContact>();
this.arraylist.addAll(theContactsList);
Collections.sort(this.arraylist, new Comparator<SelectPhoneContact>() {
@Override
public int compare(SelectPhoneContact t1, SelectPhoneContact t2) {
if(t2.getPhone().equals("3456781276")) { // put the phone number you want on top here
return 1;
} else {
return t1.getName().compareTo(t2.getName());
}
}
});
}
因此我们基本上在适配器开始使用它之前对ArrayList进行排序。
所以在这个例子中，我正在拨打电话号码＆＃34; 3456781276＆＃34;在其他一切之上。如果电话号码不是＆＃34; 3456781276＆＃34;，它将按名称对所有项目进行排序。 （如果您不想按名称对其进行排序，请删除else声明。
希望这有帮助。
修改
在getView()中，更改：
final SelectPhoneContact data = (SelectPhoneContact) theContactsList.get(i);
为：
final SelectPhoneContact data = (SelectPhoneContact) arraylist.get(i);
像这样改变getCount()方法：
@Override
public int getCount() {
return arraylist.size();
}
像这样改变getItem()方法：
@Override
public Object getItem(int i) {
return arraylist.get(i);
}
您必须在任何地方使用arraylist，因为这是我们正在排序的列表。
答案 1 :(得分：2)
如何使用add(int index, E element)？
if (/* check your condition here: is it the number you are looking for? */) {
// insert the contact at the beginning
selectPhoneContacts.add(0, selectContact);
} else {
// insert it at the end (default)
selectPhoneContacts.add(selectContact);
}
答案 2 :(得分：1)
实现此目的的简单方法是，只使用包含电话号码的XML视图，并在默认情况下将其设置为不可见，如果列表显示，则将视图设置为可见。我希望这篇文章可以帮助你!!!
答案 3 :(得分：1)
您可以通过循环浏览联系人轻松操作ArrayList中Collections.swap();的项目位置，只需检查与您的号码匹配的号码，例如将其放在顶部：
Collections.swap(myArrayList, i, 0);
参阅：http://www.java2s.com/Code/Java/Collections-Data-Structure/SwapelementsofJavaArrayList.htm