Question

我正在使用SQL Server并拥有以下3个表：

Employees包含Name，Sales，Bonus1，Bonus2
Departments包含Name，Score
DepartmentsMembers包含Name（Employees.Name）列，部门（Departments.Name）

如何根据属于该属性的员工的Score + Sales + Bonus1的总和来计算和更新每个部门的Bonus2列的值部？

编辑：

根据Ali Adlavaran的回答，我得到了这个查询，以便返回每个部门的结果列表及其计算的Score。

SELECT 
    DepartmentsMembers.Name, SUM(Sales + Bonus1 + Bonus2)
FROM 
    DepartmentsMembers Department 
INNER JOIN
    DepartmentsMembers ON Departments.Name = DepartmentsMembers.Name 
INNER JOIN
    Employees ON DepartmentsMembers.Name = Employees.Name
WHERE 
    DepartmentsMembers.Name = Departments.Name
GROUP BY 
    DepartmentsMembers.Name

如何在每个部门的更新声明中加入所有内容？

谢谢。

Answer 1

应该是这样的：

UPDATE Departments
SET Score = 
(
  SELECT SUM(Sales + Bonus1 + Bonus2)
  FROM DepartmentsMembers 
  INNER JOIN Employees ON Employees.Name = DepartmentsMembers.Name
  WHERE DepartmentsMembers.Department =   Departments.Name
  GROUP BY DepartmentsMembers.Department
)

我希望对你有所帮助:)。

Answer 2

首先，由部门总结：

SELECT dm.Department,
       SUM(COALESCE(e.Sales, 0) + COALESCE(e.Bonus1, 0) + COALESCE(e.Bonus2, 0)) as total
  FROM DepartmentsMembers dm INNER JOIN
       Employees e
       ON dm.EmployeeName = e.Name
GROUP BY dm.Department;

然后，您可以在部门更新中使用它：

UPDATE d
    SET Score = de.total
    FROM Departments d JOIN
         (SELECT dm.Department,
                 SUM(COALESCE(e.Sales, 0) + COALESCE(e.Bonus1, 0) + COALESCE(e.Bonus2, 0)) as total
          FROM DepartmentsMembers dm INNER JOIN
               Employees e
               ON dm.EmployeeName = e.Name
          GROUP BY dm.Department
         ) de
         ON de.Department = d.Name;

编辑：

如果您想确保所有部门都得到更新，请使用LEFT JOIN：

UPDATE d
    SET Score = COALESCE(de.total, 0)  -- only needed if you don't want `NULL`s
    FROM Departments d LEFT JOIN
         (SELECT dm.Department,
                 SUM(COALESCE(e.Sales, 0) + COALESCE(e.Bonus1, 0) + COALESCE(e.Bonus2, 0)) as total
          FROM DepartmentsMembers dm INNER JOIN
               Employees e
               ON dm.EmployeeName = e.Name
          GROUP BY dm.Department
         ) de
         ON de.Department = d.Name;

使用多个表中的多个值的总和更新列值，每行

2 个答案: