Question

我尝试使用https://github.com/pybee/Python-Apple-support（python 3.5.3 ios库）

编辑：我尝试添加export default class extends Component { constructor(props) { super(props); this.state = { markers: [] value: '' } handleChange(event) { callback = () => { console.log(this.state.markers); } markers.forEach((place,index) => { ..... services.getDetails(request, (place, status) => { if(place != null){ ..... }else{ } itemsProcessed++; if(itemsProcessed === markers.length) { this.callback(); } }); }); } }，但是当我尝试包含时，它说Python / Python.h不存在。

Tweak.xm：

HackScript_PRIVATE_FRAMEWORKS = Python.framework

生成文件：

#include "Python\Python.framework\Versions\3.5\Resources\include\python3.5\Python.h"
%hook SpringBoard

- (void)applicationDidFinishLaunching:(id)application {
    %orig;

    PyObject *py_main, *py_dict;
    py_main = PyImport_AddModule("__main__");
  py_dict = PyModule_GetDict(py_main);

    PyObject *PyRes = PyRun_String("print(\"This is a test message from HackScript\")", Py_single_input, py_dict, py_dict);

    PyObject *PyResRep = PyObject_Str(PyRes);

    char *PyResCStr = PyBytes_AS_STRING(PyResRep);
    NSString *PyResStr = @(PyResCStr);

    UIAlertView *alert1 = [[objc_getClass("UIAlertView") alloc] initWithTitle:@"Welcome"
        message:PyResStr
        delegate:self
        cancelButtonTitle:@"k"
        otherButtonTitles:nil];

        [alert1 show];

        [alert1 release];
}

%end

但是当我包含Python.h并尝试访问python对象时，它会在编译时出现此错误：

export ARCHS = armv7 armv7s arm64
export TARGET = iphone:clang:8.1:8.1
export SDKVERSION=8.1

include $(THEOS)/makefiles/common.mk

TWEAK_NAME = HackScript
HackScript_FILES = Tweak.xm

include $(THEOS_MAKE_PATH)/tweak.mk

after-install::
    install.exec "killall -9 SpringBoard"

如果这不起作用，任何人都可以推荐一种脚本语言，我可以将其嵌入到我的theos调整中吗？

Answer 1

您是否已在复制阶段将Python.framework复制到二进制文件中？

请参阅GitHub上的问题部分。

iOS Tweak中的Python？

1 个答案: