我有几个数据库表。所有这些都充满了数据。我有以下PHP代码尝试检索数据：
$sql = "select inspection_date, inspection_type, capacity, criticality, man_hours from $table_name where device_number = '$device_number' order by inspection_date";
//printf("sql = $sql <br/>");
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
$final_array[] = array("device_number"=>$all_ld_formatted[$i]['device_number'], "old_device_number"=>$all_ld_formatted[$i]['old_device_number'],
"type"=>$all_ld_formatted[$i]['type'], "building"=>$all_ld_formatted[$i]['building'], "room"=>$all_ld_formatted[$i]['room'],
"power"=>$all_ld_formatted[$i]['power'], "inspection_date"=>$row['inspection_date'], "inspection_type"=>$row['inspection_type'],
"capacity"=>$row['capacity'], "criticality"=>$row['criticality'], "man_hours"=>$row['man_hours']);
}
} else {
printf("no results <p/>");
}
上面的代码在for循环中运行。那就是为什么你在那里看到$ all_ld_formatted [$ i] [＆＃39; value＆＃39;]的东西。出于某种原因，代码总是返回＆＃34;没有结果＆＃34;。但是，如果我取消注释printf（＆＃34; sql = $ sql＆＃34;）;行，并将查询复制并粘贴到PHPMyAdmin中，我总能得到我正在寻找的结果。请帮助，谢谢！
此致
Chris Martino