Question

下面的代码打印如下文本：

 John
  Smith
  02/07/1234

首先它缩进了两行，如何更改代码以将其打印为： John Smith 02/07/1234在一行？

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3:
    for forename, surname, birthdate in zip(f1,f2,f3):
        print (forename, surname, birthdate)

Answer 1

尝试：

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3:
    for forename, surname, birthdate in zip(f1,f2,f3):
        print("{} {} {}".format(forename.strip(' \t\n\r'), surname.strip(' \t\n\r'), birthdate.strip(' \t\n\r')))

.strip（'\ t \ n \ r'）删除前导和尾随标签返回和空格， .format（）格式化要打印的字符串一个很好的可控制方式。

Answer 2

使用.join并从每个名称中删除空格。

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3:
    for forename, surname, birthdate in zip(f1,f2,f3):
        print(' '.join([forename.strip(), surname.strip(), birthdate.strip()]))

从一行中的文本文件打印文本

2 个答案: