Question

我试图在一年中的某个月内找到用户首次听到的歌曲

我正在使用以下数据

user-id       date           song
.......      .......        ......
1           2017-9-30        song1
1           2017-9-10        song1
1           2017-3-12        song2
1           2017-9-01        song1
1           2017-12-31       song1
1           2017-09-12       song3
1           2017-10-11       song1
1           2017-09-09       song5
1           2017-10-08       song4
2           2017-07-12       song1
2           2017-12-31       song3
2           2017-10-12       song5
3           2017-10-11       song1
3           2017-10-09       song7
3           2017-10-08       song2
3           2017-07-12       song2

我想获得以下输出

   user-id     year       month       song     count
   .......    ......      ......      .....    ......
      1        2017        9          song1       3

我尝试过以下查询，但是我按降序获取所有数据，而我无法选择最顶层的数据

SELECT YEAR(date) AS year, MONTH(date) AS month,song,count(song) c
FROM table where id=1 and year(dt)=2017 and month(dt)=9
GROUP BY YEAR(date), MONTH(date) ,song ORDER BY c DESC

我甚至尝试过使用

SELECT d.*
FROM (SELECT id,year(date) y,month(date) m,count(song) as c,
            ROW_NUMBER() OVER (PARTITION BY month(date) ORDER BY COUNT(song) DESC) as seqnum
     FROM table where id=1 and month(date)=9
     GROUP BY month(date),year(date) song 
    ) d
WHERE seqnum = 1
ORDER BY c, dt DESC ;

它会抛出错误

编译语句时出错：FAILED：ParseException行5:37无关输入'歌'期待'附近''

Answer 1

您可以使用LIMIT：

SELECT YEAR(date) AS year, MONTH(date) AS month,song,count(song) c
FROM table 
GROUP BY YEAR(date), MONTH(date) ,song 
ORDER BY c DESC
LIMIT 1

在给定的月份和年份中，用户最喜欢的歌曲

1 个答案: