如何在symfony上使用Route注释匹配URI

Question

示例案例URI：＆＃39; / department / id / 1＆＃39;

控制器：

/**

     @Route/department/id/{slug}
*/
        function($slug)
        return new Response($slug)

它返回我＆＃39; 1＆＃39;

如果我有URI： / department / id / 1 / category / id / 2

如何形成捕获1和2的@Route？

请帮助谢谢

Answer 1

/**
 @Route(/department/{slug}/category/{id}, name='department_category_detail')
*/
public function departmentCagetegoryDetailAction($slug, $id) {
    ....
}