Question

假设customPassFile.txt中有两行。第一行是＆＃34; 123测试＆＃34;第二行是＆＃34; testing321＆＃34;。如果passwordCracking =＆＃34; 123testing＆＃34;，那么输出将是＆＃34; 123testing＆＃34;在文件中找不到（或类似的东西）。如果passwordCracking =＆＃34; testing321＆＃34;，那么输出将是＆＃34; testing321＆＃34;在文件中找到了。我认为我所拥有的for循环只是读取文本文件的最后一行。解决这个问题的任何解决方案？

import time
import linecache

def solution_one(passwordCracking):
    print("Running Solution #1 @ " + time.strftime("%Y-%m-%d %H:%M:%S",time.localtime()))
    startingTimeSeconds = time.time()
    currentLine = 1
    attempt = 1
    passwordFound = False
    wordListFile = open("customPassFile.txt", encoding="utf8")
    num_lines = sum(1 for line in open('customPassFile.txt'))
    while(passwordFound == False):
        for i, line in enumerate(wordListFile):
           if(i == currentLine):
                line = line
        passwordChecking = line
        if(passwordChecking == passwordCracking):
            passwordFound = True
            endingTimeSeconds = time.time()
            overallTimeSeconds = endingTimeSeconds - startingTimeSeconds
            print("~~~~~~~~~~~~~~~~~")
            print("Password Found: {}".format(passwordChecking))
            print("ATTEMPTS: {}".format(attempt))
            print("TIME TO FIND: {} seconds".format(overallTimeSeconds))
            wordListFile.close()
            break
        elif(currentLine == num_lines):
            print("~~~~~~~~~~~~~~~~~")
            print("Stopping Solution #1 @ " + time.strftime("%Y-%m-%d %H:%M:%S", time.localtime()))
            print("REASON: Password could not be cracked")
            print("ATTEMPTS: {}".format(attempt))
            break
        else:
            attempt = attempt + 1
            currentLine = currentLine + 1
            continue

Answer 1

**我会在OP了解缩进的问题后删除这个答案，因为我理解他的代码意图。*

ifelse

这里你的代码在for循环之外，所以只缓存了最后一行。

for i, line in enumerate(wordListFile):
   if(i == currentLine):
        line = line
passwordChecking = line
#rest of the code.

当我打开文本文件时，它只读取最后一行

1 个答案: