Python数组组计数

Question

在Python中，我有一个数组，

("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")

我需要输出显示计数

("192.168.1.1","high",2),("192.168.1.1","low",2),("192.168.1.2","high",1),("192.168.1.2","medium",1)

任何人都请帮助我

Answer 1

您可以使用收藏品中的计数器。

from collections import Counter

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

counter = Counter(l)

result = [(*key, counter[key]) for key in counter]

Answer 2

如果您不关心订单：

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

list(set([(*t, l.count(t)) for t in l]))