我正在从angular转向vue并试图将'service'作为一个简单的typescript类实现。我想知道我会怎么做,目前我有:
import axios from 'axios'
import keys from 'libs/keys/api-keys'
export default class Google {
textSearch(query: string, radius = 5000) {
let url = `https://maps.googleapis.com/maps/api/place/textsearch/json?radius=${radius}&query=${query}` +
`&key=${keys.googleApiKey}`
return axios.get(url)
}
getPhoto(photoReference: string, maxwidth = 1600) {
let url = `https://maps.googleapis.com/maps/api/place/photo?maxwidth=${maxwidth}` +
`&photoreference=${photoReference}&key=${keys.googleApiKey}`
return axios.get(url)
}
}
作为我的班级。然后我尝试将其导入我的vue组件:
import google from 'src/libs/location/google'
google.textSearch(params.location)
但是我收到了错误:
Property 'textSearch' does not exist on type 'typeof Google'
所以我尝试在课前抛出一个默认界面,但仍然得到同样的错误:
import axios from 'axios'
import keys from 'libs/keys/api-keys'
export default interface Google {
textSearch(query: string, radius?: number): void
}
export default class Google {
textSearch(query: string, radius = 5000) {
let url = `https://maps.googleapis.com/maps/api/place/textsearch/json?radius=${radius}&query=${query}` +
`&key=${keys.googleApiKey}`
return axios.get(url)
}
getPhoto(photoReference: string, maxwidth = 1600) {
let url = `https://maps.googleapis.com/maps/api/place/photo?maxwidth=${maxwidth}` +
`&photoreference=${photoReference}&key=${keys.googleApiKey}`
return axios.get(url)
}
}
这样做的正确方法是什么?类型是否必须在外部.d.ts文件中?如果是这样,打字稿将如何在导入时推断出类型。