Question

我试图创建自己的博客网站，其中可能包含很长的故事（来自数据库中的一个字段）。我在其他视图上成功创建了记录列表（故事列表）的分页，并尝试从Django文档中进行实验。我所做的是从非常长的字符串创建一个数组，所以django分页可以计算它。

＆＃34; views.py＆＃34;

def post_detail(request, slug=None):  #retrieve
instance = get_object_or_404(Post, slug=slug)

words_list = instance.content.split()
paginator = Paginator(words_list, 500)  # Show 25 contacts per page

page = request.GET.get('page')

try:
    words = paginator.page(page)
except PageNotAnInteger:
    # If page is not an integer, deliver first page.
    words = paginator.page(1)
except EmptyPage:
    # If page is out of range (e.g. 9999), deliver last page of results.
    words = paginator.page(paginator.num_pages)

if instance.draft or instance.publish > timezone.now().date():
    if not request.user.is_staff or not request.user.is_superuser:
        raise Http404
share_string = urlquote_plus(instance.content)
context = {
    "title": instance.title,
    "instance": instance,
    "share_string": share_string,
    "word_content": words,
}

return render(request, "post_detail.html", context)

我成功创建了它，但是作为一个从上到下的单词列表而不是段落格式，它看起来并不好看。

＆＃34; post_detail.html＆＃34;

{% for word_con in word_content %}
            <p class="text-justify">{{ word_con }}</p>
{% endfor %}

我试图用它来结合它：

{% for word_con in word_content %}
            <p class="text-justify">{{ ' '.join(word_con) }}</p>
{% endfor %}

但是收到错误。

Answer 1

我终于找到了解决方法来完成这项工作。这不是最好的分辨率，但对我有用。

def post_detail(request, slug=None):  #retrieve
instance = get_object_or_404(Post, slug=slug)

#Detect the breaklines from DB and split the paragraphs using it
tempInstance = instance.content
PaginatedInstance = tempInstance.split("\r\n\r\n")

paginator = Paginator(PaginatedInstance, 5)  #set how many paragraph to show per page

page = request.GET.get('page', 1)

try:
    Paginated = paginator.page(page)
except PageNotAnInteger:
    Paginated = paginator.page(1)
except EmptyPage:
    Paginated = paginator.page(paginator.num_pages)

context = {
    "Paginated": Paginated,  #will use this to display the story instead of instance (divided string by paragraph)
}

return render(request, "template.html", context)

我没有统计所有字符，而是决定将每个段落的字符串拆分并保存在一个数组中，这就是我在模板文件中分页的那个

{% for paginatedText in Paginated %}
        {{ paginatedText }}
{% endfor %}

非常长的字符串Django 1.11（Python 3.6）的分页

1 个答案: